Answer:
4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2
Explanation:
Nitroglycerin has a chemical formula C3H5N3O9. The balanced chemical equation is as follows:
4 C3H5N3O9 ------> 6N2 + O2 + 10H2O + 12CO2
We suppose that in a reaction, 44g of carbon dioxide is produced. The mass of nitroglycerin that must have reacted will be calculated as under:
Molecular mass of Nitroglycerin = 227g/mol
Molecular mass of Carbon dioxide = 44g/mol
No. of moles of carbon dioxide produced = 44/44 = 1 mole produced.
Now, from balanced chemical equation, we can see that
12 moles of carbon dioxide are produced by = 4 moles of nitroglycerin.
1 mole of carbon dioxide is produced by = 4/12 = 1/3 moles of nitroglycerin.
Mass of nitroglycerin which produced 1 mole of carbon dioxide = 1/3 x 227 = 75.666 grams.
Atomic mass Cu = 63.546 a.m.u
63.546 g ---------------- 6.02x10²³ atoms
22 g --------------------- ??
22 x (6.02x10²³ ) / 63.546 => 2.08x10²³ atoms
hope this helps!
Explanation :
In thermodynamics, a system is region or part of space which is being studied and observed while the surrounding is the region or space around the system which interacts with the system.
Here in the experiment ,system which is observed is reaction or changes when citric acid and sodium bicarbonate are mixed together. And the mixing is carried out in the calorimeter which serves as a surrounding around the system.
The reason behind the using the calorimeter is measure the energy change occurring during the reaction.
Answer:
Percentage yield = 85.2%
Explanation:
Given data:
Mass of Mg = 21.3 g
Actual yield of MgO = 30.2 g
Percentage yield = ?
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg = mass/molar mass
Number of moles of Mg = 21.3 g / 24.3 g/mol
Number of moles of Mg = 0.88 mol
Now we will compare the moles of MgO with Mg.
Mg : MgO
2 : 2
0.88 : 0.88
Mass of MgO:
Mass of MgO= moles × molar mass
Mass of MgO= 0.88 mol × 40.3g/mol
Mass of MgO = 35.46 g
Actual yield of MgO = 30.2 g
Percentage yield:
Percentage yield = Actual yield/theoretical yield × 100
Percentage yield = 30.2 g/ 35.46 g × 100
Percentage yield = 85.2%
