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erma4kov [3.2K]
3 years ago
7

If you had a 0.550 L solution containing 0.0250 M of Cr3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all o

f the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.
Chemistry
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

0.032 L of NaOH

Explanation:

The reaction is;

Cr^3+(aq) + 3OH^- (aq) -----> Cr(OH)3(s)

Amount of Cr^3+ = 0.550 × 0.0250 = 0.01375 moles

If 1 mole of Cr^3+ reacts with 3 moles of OH^-

0.01375 moles of Cr^3+ reacts with 0.01375 moles × 3/1

= 0.04125 moles of OH^-

Hence we need 0.04125 moles/1.27 M = 0.032 L of NaOH

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The masses of the nucleus and the electron cloud of an atom is balanced if false. Do you have any answer options??
4 0
3 years ago
Please help me with this question!! I’m not sure if they’re the insoluble ions that precipitate with chromate or the soluble one
Vika [28.1K]

Answer:

2) Copper (II) Chloride

Explanation:

A precipitate will form if the resulting compound is insoluble in water. For example, a silver nitrate solution (AgNO3) is mixed with a solution of magnesium bromide (MgBr2).

4 0
2 years ago
An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
sleet_krkn [62]

Answer:

Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+

Explanation:

The total number of proton present in an atom is known as the atomic number of that atom.From that point of view the atomic number of iron ion is 26.

  The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton

 According to the given question iron ion contain 3 more protons than electrons as a result the iron ion will contain 3 unit positive charge.

5 0
3 years ago
How many moles of ethanol are produced starting with 500.g glucose?
Monica [59]
<h3>Answer:</h3>

5.55 mol C₂H₅OH

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

[Given] 500. g C₆H₁₂O₆ (Glucose)

[Solve] moles C₂H₅OH (Ethanol)

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH

[PT] Molar mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up conversion:                                                                                 \displaystyle 500 \ g \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{180.18 \ g \ C_6H_{12}O_6})(\frac{2 \ mol \ C_2H_5OH}{1 \ mol \ C_6H_{12}O_6})
  2. [DA} Multiply/Divide [Cancel out units]:                                                         \displaystyle 5.55001 \ mol \ C_2H_5OH

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH

8 0
3 years ago
A sample of iron metal is placed in a graduated cylinder. it is noted that 10.4 ml of water is displaced by the iron. the iron i
Pavel [41]
<h3>Answer:</h3>

                 162.43 g of FeCl₂

<h3>Explanation:</h3>

Step 1: Calculate mass of Fe;

As,

                                   Density  =  Mass ÷ Volume

Or,

                                   Mass  =  Density × Volume

Where Volume is the volume of water displaced  =  10.4 mL

Putting values,

                                   Mass  =  7.86 g.mL⁻¹ × 10.4 mL

                                   Mass  =  81.744 g of Fe

Step 2: Calculate amount of FeCl₂;

The balance chemical equation is as follow,

                                Fe  +  2 HCl   →    FeCl₂  +  H₂ ↑

According to this equation,

       55.85 g (1 mol) Fe produced  =  110.98 g (1 mol) of FeCl₂

So,

               81.744 g Fe will produce  =  X g of FeCl₂

Solving for X,

                    X  =  (81.744 g × 110.98 g) ÷ 55.85 g

                     X =  162.43 g of FeCl₂

7 0
3 years ago
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