Answer:
0.214 L
Explanation:
Step 1: Write the balanced equation
This is a single displacement reaction.
Zn(s) + 2 HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)
Step 2: Calculate the moles corresponding to 0.625 g of Zn
The molar mass of Zn is 65.38 g/mol.
0.625 g × 1 mol/65.38 g = 9.56 × 10⁻³ mol
Step 3: Calculate the moles of H₂ produced from 9.56 × 10⁻³ moles of Zn
The molar ratio of Zn to H₂ is 1:1. The moles of H₂ produced are 1/1 × 9.56 × 10⁻³ mol = 9.56 × 10⁻³ mol.
Step 4: Calculate the volume occupied by 9.56 × 10⁻³ moles of hydrogen
Assuming standard pressure and temperature, 1 mole of hydrogen occupies 22.4 L.
9.56 × 10⁻³ mol × 22.4 L/1 mol = 0.214 L
Answer:
2.41 g of NaCl is needed
Explanation:
Molarity of solution = (Number of moles of solute)/(Volume of solution in Litre)
Here sodium chloride (NaCl) is solute in saline solution
275 mL = 0.275 L
So, number of moles of NaCl in 275 mL saline solution =
Molar mass of NaCl = 58.44 g/mol
Number of moles = (mass)/(molar mass)
So, mass of 0.04125 moles of NaCl =
So, 2.41 g of NaCl is needed
Answer:
Intermolecular forces (IMFs) can be used to predict relative boiling points. The stronger the IMFs, the lower the vapor pressure of the substance and the higher the boiling point. Therefore, we can compare the relative strengths of the IMFs of the compounds to predict their relative boiling points.
Explanation:
Answer:
Tetrahedral. Tetra- signifies four, and -hedral relates to a face of a solid; “tetrahedral” literally means “having four faces. ” This shape is found when there are four bonds all on one central atom, with no lone electron pairs. In accordance with the VSEPR theory, the bond angles between the electron bonds are 109.5o ...
Given:
mass of chlorine = 31.5 grams Cl2
temperature of water = 35 degrees C
volume of chlorine = 15 L
*water levels are equal
assume ideal gas behavior
Vapor pressure of water at 35 C = 42.2 torr
To solve for the barometric pressure, use the ideal gas equation:
PV = nRT
where P = Pgas - Pwater
(Pgas - 42.2 torr) * 15 L = 31.5g/70.9g/mol * (35 + 273) K * (760 torr * 22.4 L/298K)
solve for Pgas
Pgas = 563.36 torr
Therefore, the barometric pressure is 563.36 torr.