Los electrolitos son sustancias que se disocian en agua para dar iones.
Generalmente en química, podemos clasificar sustancias como
Los electrolitos pueden disociarse en solución para producir iones, pero un no electrolito no puede hacer eso.
Entre los electrolitos hay dos clases;
Los electrolitos fuertes se disocian completamente en solución, mientras que los electrolitos débiles no se disocian completamente en solución.
El hecho de que los electrolitos débiles no se disocien por completo significa que algunas moléculas de la sustancia no se disocian.
Por lo tanto, si los ácidos nitroso y fluorhídrico se describen como electrolitos débiles, esto significa que hay moléculas en la solución que no están disociadas.
Lea más: brainly.com/question/14566383
<span>Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present. The balanced chemical equation is shown below.
Cu + 2AgNO3 ---> Cu(NO3)2 + 2Ag
The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in grams, of Ag is produced from reaction of 31.75 g of Cu?
26.95
107.9
215.91
431.82</span>
Answer:
The concentration of the resulting solution in parts per million is 177.97
Explanation:
Parts per million (ppm), is a unit of measure for concentration that refers to the number of units of the substance per million units of the set.
The concentration in parts per million expressed in mass / mass is calculated by dividing the mass of the solute (ms) by the mass of the solution (md, sum of the mass of the solute and the mass of the solvent), both expressed in the same unit and multiplied by 10⁶ (1 million).
So, being:
- md: 0.089 grams of KI + 500 grams of H₂O= 500.089 grams
Replacing:
ppm= 177.97
<u><em>The concentration of the resulting solution in parts per million is 177.97</em></u>
Answer is: mass of barium sulfate is 0.668 grams.
Chemical reaction: BaCl₂ + Na₂SO₄ → BaSO₄<span> + 2NaCl.
V(</span>BaCl₂) = 25.34 mL ÷ 1000 mL/L = 0.02534 L.
c(BaCl₂) = 0.113 mol/L.
n(BaCl₂) = V(BaCl₂) · c(BaCl₂).
n(BaCl₂) = 0.02534 L · 0.113 mol/L.
n(BaCl₂) = 0.00286 mol.
From chemical reaction: n(BaCl₂) : n(BaSO₄) = 1 : 1.
n(BaSO₄) = 0.00286 mol.
m(BaSO₄) = n(BaSO₄) · M(BaSO₄).
m(BaSO₄) = 0.00286 mol · 233.4 g/mol.
m(BaSO₄) = 0.668 g.
