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vladimir2022 [97]
2 years ago
12

How can you verify that metals conduct electricity and explain​

Chemistry
1 answer:
Ann [662]2 years ago
4 0

Answer:

delocalised electrons

Explanation:

In a metal there are delocalised(free) electrons which means they carry electrical charge through the metal.

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Rows are periods, columns are groups

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A solution that holds more solute than it normally can under the conditions at a given temperature is _____.
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It would be super saturated
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Which components of the atom have a positive charge?
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Write ionic equations for the following:<br> HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)
vodomira [7]

Answer:

HCl(aq) + KOH(aq) ===> H2O(l) + KCl(aq)

Note the stoichiometry of the balanced equations shows us that HCl and KOH react in a 1:1 mole ratio. So, let us find moles of HCl and moles of KOH that are present:

moles HCl = 250.0 ml x 1 L/1000 ml x 0.25 mol/L = 0.06250 moles HCl

moles KOH = 200.0 ml x 1 L/1000 ml x 0.40 mol/L = 0.0800 moles KOH

You can see that there are more moles of KOH than there are of HCl, meaning that KOH is in excess and after neutralizing all of the HCl, the solution will be left with excess KOH making the pH > 7 = BASIC

4 0
1 year ago
Show the calculation of the molar mass (molecular weight) of a solute if a solution of 5.8 grams of the solute in 100 grams of w
Leni [432]

Answer : The molar mass of solute is, 89.9 g/mol

Explanation : Given,

Mass of solute = 5.8 g

Mass of solvent (water) = 100 g

Formula used :  

\Delta T_f=K_f\times m\\\\T_f^o-T_f=T_f\times\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of water}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure solvent (water) = 0^oC

T_f = temperature of solution = 1.20^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0^oC)-(1.20^oC)=1.86^oC/m\times \frac{5.8g\times 1000}{\text{Molar mass of solute}\times 100g}

\text{Molar mass of solute}=89.9g/mol

Therefore, the molar mass of solute is, 89.9 g/mol

5 0
3 years ago
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