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inysia [295]
3 years ago
12

Science / which phrase describes the differences between these two liquid ?

Chemistry
1 answer:
Zina [86]3 years ago
8 0

Answer:

viscosity

Explanation:

one one left is mercury and the other one is honey right?

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Heat is being transferred from the ground to the air above it by conduction. Explain how this is possible.
Klio2033 [76]

Answer:

Conduction directly affects air temperature only a few centimeters into the atmosphere. During the day, sunlight heats the ground, which in turn heats the air directly above it via conduction. At night, the ground cools and the heat flows from the warmer air directly above to the cooler ground via conduction.

Explanation:

4 0
3 years ago
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What is the molality of a solution that is obtained by dissolving 2.922 g of NaCl into 1000.0 g of water if the molar mass of Na
never [62]
In order to find molarity, you must first find the number of moles that was dissolved.

Now, Moles = Mass ÷ Molar Mass
                   
⇒  Moles of NaCl  = 2.922 g ÷ 58.44 g/mol 
                       
                               = 0.05 moles

∴ the Molarity of the NaCl is 0.05 M [Option 1]
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3 years ago
Will give brainliest to the correct answer
Pavel [41]
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3 years ago
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What are the laws of Newton?
Tanzania [10]

Answer:

an object that is at rest will stay at rest inless a force acts upon it.

An oject that is in motion will not change its velocity unless a force acts upon it.

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3 years ago
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A hydrocarbon contains 85.7% carbon and the remainder
Viefleur [7K]

Answer:

CH₂ ;  67.1 %

Explanation:

To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation

Assume 100 grams of the compound.

# mol C = 85.7 g / 12.01 g/mol = 7.14 mol

# mol H = 14.3 g /  1.008 g/mol = 14.19 mol

The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C

So the empirical formula is CH₂

For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄  reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.

We need to calculate the moles of  NaBH₄ ( M.W = 37.83 g/mol )

1.203 g  NaBH₄ / 37.83 g/mol =  0.0318 mol

Theoretical yield from balanced chemical equation:

0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆

Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol =  0.440 g

% yield = 0.295 g/ 0.440 g x 100 = 67.1 %

6 0
3 years ago
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