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stepladder [879]
3 years ago
9

Acetic acid is the active ingredient in vinegar. In a solution of acetic acid the following equilibrium is established. HC2H3O2(

aq) <--> H+(aq) + C2H3O2-(aq) The equilibrium constant for this reaction is 1.8 x 10–5. What is the equilibrium constant for the following reaction ? H+(aq) + C2H3O2-(aq) <--> HC2H3O2(aq)
Chemistry
1 answer:
lana [24]3 years ago
6 0

Answer:

the equilibrium constant is 1.8 x 10⁻5 and strongly favor the reactants.

Explanation:

the chemical reaction provided for the two equation are the same but different direction i.e a reversible reaction. Assuming, the mass of reactants and product and temperature remain constant.

therefore, the equilibrium constant K, is 1.8 x 10⁻5. this is a very small value of K, thereby strongly favor the backward direction to form reactant.

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Leya [2.2K]

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E. a small yellow ball that represents the Sun

Explanation:

key word on the question, 'physical'

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3 years ago
How do different bridge designs react to stong winds
anastassius [24]

Depending on how the design is, The bridge will sway, bounce, or move in some way. If the bridge was too stiff the winds would destroy the bridge and cause it to crumble and fall.

Hope that answer works for you! :)

3 0
3 years ago
A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
2 years ago
If an object absorbs light energy it's thermal energy ______ .
kolezko [41]
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3 0
3 years ago
Balance the following
olga55 [171]

Answer:

Your coefficients (the numbers in front of the molecule) will be the following from left to right.

1. <u>1 - 2 - 1 - 2</u>

2. <u>2 - 1 - 2 - 2 - 1</u>

3. <u>2 - 4 - 1</u>

4. <u>2 - 4 - 3</u>

5. <u>2 - 2 - 2 - 1</u>

6. <u>1 - 1 - 1</u>

7. <u>2 - 1 - 2</u>

8. <u>3 - 1 - 2 - 3</u>

9. <u>3 - 1 - 2 - 3</u>

10. <u>2 - 1 - 1 - 1</u>

Explanation:

To balance this equations first count how many times an element is on each side and then see what needs to be changed in order to balance them.

8 0
1 year ago
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