Answer:
Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)
Explanation:
There are three steps you must follow. You must write the:
- Molecular equation
- Ionic equation
- Net ionic equation
A. Molecular equation
BaCl₂(aq) + Na₂SO₄(aq) ⟶ BaSO₄(s) + 2NaCl(aq)
B. Ionic equation
You write all the soluble substances as ions.
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
C. Net ionic equation
To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.
Ba²⁺(aq) + <u>2Cl⁻(aq) </u>+ <u>2Na⁺(aq</u>) + SO₄²⁻(aq) ⟶ BaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2Cl⁻(aq)
</u>
The net ionic equation is
Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)
Answer:
I don't see a specific question, so I'll make a few comments and hope that answers the reason for the post.
Explanation:
Zinc(Zn) does react with iron chloride, since zinc is a more reactive metal than the iron.
When Zn is introduced to an iron (III) chloride solution, the Zn disoplaces the Fe atom in a displacement reaction.
The chemical equation of the reaction:
Zn + Fe(III)Cl3 → ZnCl3 + Fe
Energy is often realeased in this type of reaction, since the resulting chemical products have a lower energy that the reactants.
There are several metals more reactive than iron. One of the more interesting examples of a highly exothermic reaction with iron chloride (rust) is the reaction of aluminum with iron chloride. `This is highly exothermic and is labelled a thermite reaction. It provides a spectacular flame that is not enough to weld railroad tracks together.
Answer:
33.7
Explanation:
i just know i had a question on it'
Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g
