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larisa [96]
3 years ago
13

How might observations of the sun's outermost layers reveal what's happening in the interior? and how could this information be

used to predict solar storms in the future?
Physics
2 answers:
LuckyWell [14K]3 years ago
8 0
A raging activity can be found in t<span>he Sun's interior, with pressure waves being produced and travelling back and forth, from the core to the surface and back to the core. By looking closely at the 'surface' we can see these "ripples".  It gives us an idea of how dense the material was that the waves passed through. In a way, this can help to predict solar storms in the future.</span>
UNO [17]3 years ago
5 0

Answer:

Explanation:

The core of the Sun is an active spot where fusion takes place and high pressure dense waves are formed that travel from core to surface and then back to core.

These waves are strong and describes the reaction and its amount taking place in its core. These waves cause ripples at the surface which gives an idea how dense waves are and the material from which they are passes through.

This helps to predict the solar storm in future by examining the amount of heat produced at the surface and the ripple caused by waves.

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Air expands adiabatically in a piston–cylinder assembly from an initial state where p1 = 100 lbf/in.2, v1 = 3.704 ft3/lb, and T1
lutik1710 [3]

Answer:

Final temperature is equal to 1291.63°R  

Explanation:

given,

p₁ = 100 lb f/in²,               v₁ = 3.704 ft³/lb,           and T₁ = 1000 °R

p₂ = 30 lb f/in²                 n = 1.4

Δ u = 0.171(T₂ - T₁)

we know for poly tropic process

p vⁿ = constant

p₁ v₁ⁿ = p₂ v₂ⁿ

100 × 3.704¹°⁴ = 30 × v₂¹°⁴

v₂ = 8.753 ft³/lb

work done for poly tropic process

W = \dfrac{p_1v_1-p_2v_2}{n-1}

    = \dfrac{100\times 3.704-30\times 8.753}{1.4-1}

    = 269.525 lbf/in².ft³

W = \dfrac{269.525}{5.40395} Btu/lb

   = 49.87 Btu/lb

in the piston cylinder arrangement air is expanding acrobatically

Δ q = Δu + w

Δ u = - w

0.171(T₂ - T₁) = -49.87

0.171(T₁ - T₂) = -49.87

0.171 T₂ = 0.171 × 1000 + 49.87

T₂ = 1291.63 °R

Final temperature is equal to 1291.63°R  

5 0
3 years ago
When the temperature of ice-cold water is increased slightly, does it undergo a net expansion or net contraction?
miss Akunina [59]

From the freezing temperature up to about 4°C (39°F) the water CONTRACTS.  That is, it becomes MORE dense.  I think I read that water is the ONLY known substance whose solid phase floats in its liquid phase.  That's why the cubes float in your soda and bergs float in the ocean.  And if weren't so, then life on Earth would not be possible !  Oceans and lakes would freeze from the bottom up, ONE TIME, and then never thaw again.

4 0
2 years ago
Barry is conducting an experiment and rolls a tennis ball down a ramp. Which best describes the motion of the tennis ball? It do
yawa3891 [41]

Answer:

A. It does not exhibit projectile motion and follows a straight path down the ramp.

7 0
3 years ago
Read 2 more answers
Calculate the mass of 1.35 moles of sodium chloride (NaCl).
Harlamova29_29 [7]

Answer:d

Explanation:

4 0
2 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

6 0
3 years ago
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