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larisa [96]
4 years ago
13

How might observations of the sun's outermost layers reveal what's happening in the interior? and how could this information be

used to predict solar storms in the future?
Physics
2 answers:
LuckyWell [14K]4 years ago
8 0
A raging activity can be found in t<span>he Sun's interior, with pressure waves being produced and travelling back and forth, from the core to the surface and back to the core. By looking closely at the 'surface' we can see these "ripples".  It gives us an idea of how dense the material was that the waves passed through. In a way, this can help to predict solar storms in the future.</span>
UNO [17]4 years ago
5 0

Answer:

Explanation:

The core of the Sun is an active spot where fusion takes place and high pressure dense waves are formed that travel from core to surface and then back to core.

These waves are strong and describes the reaction and its amount taking place in its core. These waves cause ripples at the surface which gives an idea how dense waves are and the material from which they are passes through.

This helps to predict the solar storm in future by examining the amount of heat produced at the surface and the ripple caused by waves.

You might be interested in
When you jump,you push the earth downward.Why can’t you tell that the earth has moved?
Nonamiya [84]

The movement of the earth is so small, especially compared to you, that you don't realize it. This is because the earth's mass is so much greater than your mass.

4 0
3 years ago
Objects 1 and 2 attract each other with a gravitational force
snow_tiger [21]

Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})

using eqn (1):

F' = 9(18 units)

<u>F' = 162 units</u>

7 0
3 years ago
A radio receiver has an effective resistance of 300 Ω to the input signal on the antenna downlead. The signal voltage is 700 µV.
White raven [17]

Answer:

I = 2.33 µA

Explanation:

given,

Effective resistance (R)= 300 Ω

Voltage of signal (V)= 700 µV

current flow in the antenna = ?

Using ohm's law

V = I R

where I is the current flow

I = \dfrac{V}{R}

I = \dfrac{700\times 10^{-6}}{300}

      I = 2.33 x 10⁻⁶ A

      I = 2.33 µA

Hence, the current flow in the antenna downloaded is equal to I = 2.33 µA

6 0
3 years ago
Read 2 more answers
A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is release
DiKsa [7]

Answer:

The charge on the bead is  q = 6.084 *10^{-7}\ C

Explanation:

From the question we are told that

     The  mass of the bead is  m  =  3.6 \ g =  0.0036 \ kg

      The  magnitude of the electric field is  E =  200,000 \ N/C

       The  acceleration of the bead is  a =  24 m/s^2

Generally,  the  electric force on the bead is  mathematically represented as  

         F_ e =  q E

Where q is the charge on the bead

   Now the gravitational force opposing the upward movement of the bead is  mathematically represented as

       F_g  =  mg

Generally the net force on the bead is  mathematically represented as

       F  =  F_e - F_g = m* a

=>    qE -  mg  = ma

Now substituting values

       q *  200000 -   0.0036 *9.8   = 0.0036 * 24

     q = 6.084 *10^{-7}\ C

6 0
3 years ago
How long have us been attempting space travel?
chubhunter [2.5K]
The first attempt was made in 1957
7 0
4 years ago
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