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larisa [96]
3 years ago
13

How might observations of the sun's outermost layers reveal what's happening in the interior? and how could this information be

used to predict solar storms in the future?
Physics
2 answers:
LuckyWell [14K]3 years ago
8 0
A raging activity can be found in t<span>he Sun's interior, with pressure waves being produced and travelling back and forth, from the core to the surface and back to the core. By looking closely at the 'surface' we can see these "ripples".  It gives us an idea of how dense the material was that the waves passed through. In a way, this can help to predict solar storms in the future.</span>
UNO [17]3 years ago
5 0

Answer:

Explanation:

The core of the Sun is an active spot where fusion takes place and high pressure dense waves are formed that travel from core to surface and then back to core.

These waves are strong and describes the reaction and its amount taking place in its core. These waves cause ripples at the surface which gives an idea how dense waves are and the material from which they are passes through.

This helps to predict the solar storm in future by examining the amount of heat produced at the surface and the ripple caused by waves.

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saw5 [17]
36km/h=10m/s
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2 years ago
Brainliest if correct Question 1 of 10
Artyom0805 [142]

Answer:

B

Explanation:

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2 years ago
You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
Citrus2011 [14]

Answer:

\triangle x=3.2*10^-^5 m

Explanation:

From the question we are told that

Height of circular cylinder is h= 1.8m

Diameter of cylinderD=4cm=>0.04m

Horizontal Force  F=900N

Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\

Generally the formula for shear modulus is mathematically represented by

G=\frac{\tau}{\gamma}

Where

G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain

G=\frac{F/A}{\triangle x/L}

G=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900}{\pi r^2}  *\frac{1.8}{\triangle x}

{\triangle x} =\frac{1620}{\pi r^2* 4.0*10^1^0}

\triangle x=3.2*10^-^5 m

5 0
2 years ago
State Pascal’s law. (2) b) The area of one end of a U-tube is 0.01 m2 and that of the other
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Answer:

Pascal Law's says that:

If the area of one end of a U-tube is A, and the area of the other end is A'. then if we apply a force F in the first end (the one of area A), the force experienced at the other end must be:

F' = F*(A'/A).

b) Now we can apply this to our particular case:

if the area of one end is 0.01m^2, and the area of the other end is 1m^2

Then we have:

A = 0.01m^2

A' = 1m^2

So, if now we apply a force F in the first end, the force experienced at the other end will be:

F' = F*(1m^2/0.01m^2) = F*100

This means that the force in the other end must be 100 times the force in the first end.

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Scrat [10]
Well here in the sticks we call 'em fletchings haha

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3 years ago
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