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2 years ago

5

A 75.0 kg driver slides into a seat in a truck that has only 1 spring. The spring compresses 1.60 cm = 0.0160 m. What is the spr

ing constant of the spring in the seat?

1 answer:

ValentinkaMS [17]2 years ago

5 0

Answer

0.510

Explanation:

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If a golf ball and a ping-pong ball both move with the same kinetic energy, which has the greater speed? 1. the golf ball 2. can

schepotkina [342]

Think about it like this, the more mass there is, the faster its going to go. If you took a golf ball and a ping pong ball and you held them each separately, you would notice that the golf ball is heavier. If they move with the same kinetic energy, but the golf ball WEIGHS more, then the golf ball will have the greater speed. If you think about it, the ping pong ball may be taking its time to get to wherever its going.

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3 years ago

If a 50 N block experiences a force of kinetic friction of 11 N

ankoles [38]

Answer:

F(friction) = μ M g definition of frictional force

μ = F / (M g) = 11 N / 50 N = .22

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2 years ago

How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at

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Well you of course have different kinetic energies with the two speeds.
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The vehicle's mass is the same in both cases, so we can ignore that as well as 1/2 since it's a constant.
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which is 900 vs 3600
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3 years ago

A high jumper jumps over a bar that is 2 m above the mat. With what velocity does the jumper strike the mat in the landing area?

docker41 [41]

Answer:

The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.

Explanation:

It is given that,

A high jumper jumps over a bar that is 2 m above the mat, h = 2 m

We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

$v=\sqrt{2gh}$

g is acceleration due to gravity

$v=\sqrt{2\times 9.81\ m/s^2\times 2\ m}$

v = 6.26 m/s

So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.

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3 years ago

A rectangular loop of wire with width w = 5 cm, length L = 10cm, mass m = 40 g, and resistance R = 20 mΩ has an initial velocity

zhuklara [117]

Answer:

The loop penetrate 4 cm into the magnetic field.

Explanation:

Given that,

Width w= 5 cm

Length L= 10 cm

mass m = 40 g

Resistance R = 20 mΩ

Initial velocity = 1 m/s

Magnetic field = 2 T

We need to calculate the induced emf

Using formula of emf

$\epsilon=v_{0}Bw$

Put the value into the formula

$\epsilon =1\times2\times5\times10^{-2}$

$\epsilon =10\times10^{-2}\ volt$

We need to calculate the current

Using Lenz's formula

$i=\dfrac{\epsilon}{R}$

$i=\dfrac{10\times10^{-2}}{20\times10^{-3}}$

$i=5\ A$

We need to calculate the force

Using formula of force

$F=i(\vec{w}\times\vec{B})$

$F=iwB$

Put the value into the formula

$F=5\times5\times10^{-2}\times2$

$F=0.5\ N$

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{F}{m}$

Put the value in to the formula

$a=\dfrac{0.5}{40\times10^{-3}}$

$a=12.5\ m/s^2$

We need to calculate the distance

Using equation of motion

$v^2=u^2+2as$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{0-1^2}{2\times(-12.5)}$

$s=0.04\ m$

$s=4\ cm$

Hence, The loop penetrate 4 cm into the magnetic field.

5 0

2 years ago