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Irina-Kira [14]
2 years ago
6

Explain how energy is transferred in a food web.

Chemistry
2 answers:
Misha Larkins [42]2 years ago
7 0
Sunlight is energy, and plants use this energy to turn water and carbon dioxide into plant food. This process is called “photosynthesis”. Plants also need minerals and nutrients. Then animals consume the plants and their energy.
andrezito [222]2 years ago
5 0


<span>Energy is transferred through the separate trophic levels of a food chain or web by feeding.The first trophic level (producers) is that of plants which are examples of autotrophs – they make their own food. Photosynthesis occurs when the plants use solar energy and convert it into chemical energy so it can be stored in a carbon compound. Once this has happened the energy can be taken up by the primary consumers – these are in the second trophic level (herbivores and omnivores). Secondary consumers also need to gain energy in some way, and this is by eating the primary consumers that have gained energy from the producers, this means that the second trophic level has successfully transferred energy into the third level containing omnivores and carnivores. A succession in energy transferral means that a food web or food chain has a tertiary and/or quaternary trophic level which can contain carnivores and omnivores which are plant and animal eaters (this includes humans).This transfer in energy is fairly efficient for the organisms involved as around 10% of light energy that is converted into chemical energy through photosynthesis is transferred through the trophic levels, the rest is lost in respiration, as heat, faeces and urine. Not all of the energy can be passed along a food web or chain as it must be used in other things too, so it cannot be 100% efficient.</span>
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According to the below equation, how many moles of SO2 are required to generate 1.43×1024 water molecules?
podryga [215]
Make sure the equation is always balanced first. (It is balanced for this question already) 6.022 x 10^23 is Avogadro’s number. In one mole of anything there is always 6.022 x 10^23 molecules, formula units, atoms. For one mol of an element/ compound use molar mass (grams).

Multiply everything on the top = 8.61x10^47
Multiple everything on bottom= 1.20x10^24
Divide top and bottom = 7.15x10^23

Answer: 7.15x10^23 mol SO2
3 0
3 years ago
Which of the following is the BEST description of a temperate grassland ecosystem?
Likurg_2 [28]

Answer:

It is an area that is covered in grasses and wildflowers that receives enough rainfall to support the grassland but not the growth of trees.

Explanation:

8 0
2 years ago
Write an expression for "7 less than y."
victus00 [196]

Answer:

y-7

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4 0
3 years ago
Read 2 more answers
1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation
Rasek [7]

Answer:

Q1: 728.6 J.

Q2:

a) 668.8 J.

b) 0.3495 J/g°C.

Explanation:

<em>Q1: Calculate the energy change (q) of the surroundings (water) using the enthalpy equation:</em>

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(24.9 mL) = 24.9 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 32.2°C - 25.2°C = 7.0°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (24.9 g)(4.18 J/g°C)(7.0°C) = 728.6 J.

<em>Q2:  Calculate the energy change (q) of the surroundings (water) using the enthalpy equation </em>

<em>qwater = m × c × ΔT.  </em>

<em>We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation.</em>

<em></em>

a) First part: the energy change (q) of the surroundings (water):

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(25 mL) = 25 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 31.6°C - 25.2°C = 6.4°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (25 g)(4.18 J/g°C)(6.4°C) = <em>668.8 J.</em>

<em>b) second part:</em>

<em>Q water = Q unknown metal. </em>

<em>Q unknown metal =  - </em>668.8 J. (negative sign due to the heat is released from the metal to the surrounding water).

<em>Q unknown metal =  - </em>668.8 J = m.c.ΔT.

m = 27.776 g, c = ??? J/g°C, ΔT = (final T - initial T = 31.6°C - 100.5°C = - 68.9°C).

<em>- </em>668.8 J = m.c.ΔT = (27.776 g)(c)( - 68.9°C) = - 1914 c.

∴ c = (<em>- </em>668.8)/(- 1914) = 0.3495 J/g°C.

<em></em>

3 0
3 years ago
A cylinder container is filled with air. Its radius is 6.00 cm and
Ede4ka [16]

Answer:

395.84cm³

Explanation:

V= π r² h

V= 3.14 6² 3.5

V= 3.14 36 3.5

V= 395.84

7 0
2 years ago
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