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3 years ago

How many total atoms are in C3H-NO3?

Chemistry

1 answer:

Alik [6]3 years ago

5 0

Answer:

Percent composition by element

Element Symbol # of Atoms

Hydrogen H 5

Carbon C 3

Nitrogen N 3

Oxygen O 9

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A gas sample has an initial pressure of 547 mmHg and initial volume of 0.500 L. Pressure (in atm) when the volume of the sample

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3 years ago

Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.

inysia [295]

Explanation:

$\textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}$

We are given a $2.50L$ solution which contains $135g$ of $KCl$ .

To calculate number of moles of $KCl$ present, we need to find it's molar mass from charts. Molar Mass of $KCl$ is known to be $74.55\frac{g}{Mol}$ .

Number of moles of $KCl$ present = $\frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol$

Molarity = $\frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}$

∴ Molarity of given $KCl$ solution = $0.72\frac{mol}{L}$

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3 years ago

How are radio waves transmitted

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Attractive antennas that pull the waves tword it.

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3 years ago

WHAT IS THE PERCENT BY VOLUME OF ETHANOL IN A SOLUTION THAT CONTAINS 35 mL ETHANOL IN 115 mL OF WATER?

Dmitry [639]

We need to first add both of the solution volumes together 35+115=150. Now we can divide the volume of the ethanol by the total volume 35/150=.233. To double check we can multiply the total volume by the percentage of ethanol by volume we got as a solution 150x.233=35. So the percentage by volume of ethanol in the solution is .233x100=23.3%.

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3 years ago

Convert the following Grams: 0.200 moles of H2S

ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

0.200 mol H₂S

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 6.818 \ g \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.818 g H₂S ≈ 6.82 g H₂S

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3 years ago