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mel-nik [20]
3 years ago
6

What is the molarity of a solution if you take 12.0 grams of ca(no3)2 and mix it with 0.105 l of water?

Chemistry
1 answer:
Lunna [17]3 years ago
8 0
The  molarity  of  a solution  if it tale 12.0   grams  of  Ca(No3)2  is  calculated as below

molarity =  moles/volume in liters
 moles = mass/molar mass =  12.0 g/ 164 g/mol =  0.073 moles

molarity is therefore  = 0.073/0.105 = 0.7 M 
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Read 2 more answers
Manganese forms several oxides when combined with oxygen. One of the oxides (Oxide 1) contains 63.2% of Mn and another oxide (Ox
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Explanation:

Defining law of definite proportions, it states that when two elements form more than one compound, the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers.

A. One of the oxides (Oxide 1) contains 63.2% of Mn.

Mass of the oxide = 100g

Mass of Mn = 63.2 g

Mass of O = 100 - 63.2

= 36.8 g

Ratio of Mn to O = 63.2/36.8

= 1.72

Another oxide (Oxide 2) contains 77.5% Mn.

Mass of oxide = 100 g

Mass of Mn = 77.5 g

Mass of O = 100 - 77.5

= 22.5 g

Ratio of Mn to O = 77.5/22.5

= 3.44

Therefore, the ratio of the masses of Mn and O in Oxide 1 and Oxide 2 is in the ratio 1.72 : 3.44, which is also 1 : 2. So the law of multiple proportions is obeyed.

B.

Oxide 1

Mass of Mn per 1 g of O = mass of Mn/mass of O

= 77.5/22.5

= 3.44 g/g of Oxygen.

Oxide 2

Mass of Mn per 1 g of O = mass of Mn/mass of O

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= 3.44 g/g of Oxygen.

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