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Aliun [14]
3 years ago
12

Kaia, a chemical engineering graduate, has documented all titration procedures in her project report. She refers to this report

while performing titrations in her laboratory. This is an example of _____. Select one: a. muted knowledge b. implied knowledge c. tacit knowledge d. explicit knowledge
Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

The correct option is;

d. Explicit knowledge

Explanation:

Explicit knowledge is the knowledge that can be easily articulated documented stored in a retrieval system accesses, transmitted and shared with others

Tacit knowledge is the skill developed by an individual based on actual experience such that such knowledge comprise of both facts and perspectives

Hence explicit knowledge and tacit knowledge are complementary

The operations performed by Kaia include documentation, storing in a retrieval system (her project report) and accessing what she documented, this is an example of explicit knowledge.

You might be interested in
Weather ionic or covalent, what does bonding always involve?
dezoksy [38]

Answer: Bonding always involve a pair of electrons and atoms and are shared between two non metals.

6 0
3 years ago
When N2(g) reacts with H2(g) to form NH3(g), 92.2 kJ of energy are evolved for each mole of N2(g) that reacts. Write a balanced
Naddika [18.5K]

Answer:

N₂ + 3H₂ → 2NH₃   ΔH = - 92.2KJ

Explanation:

Let's write out the chemical equation between Nitrogen and Hydrogen to Form Ammonia.

Nitrogen + Hydrogen = Ammonia

N₂ + H₂ → NH₃

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH.

The balanced stoichiometric chemical equation is given as;

N₂ + 3H₂ → 2NH₃

92.2 kJ of energy are evolved for each mole of N2(g) that reacts. And from the equation, 1 mole of N2 reacts.

The enthalpy change, ΔH = - 92.2KJ. The negative sign is because heat is being evolved.

The balanced thermochemical equation;

N₂ + 3H₂ → 2NH₃   ΔH = - 92.2KJ

6 0
3 years ago
How many mL of a stock solution of 2.00 M KNO3 are needed to prepare 100.0 mL of 0.15M KNO3? with work plz
Tatiana [17]
Using the law of dilution :

Mi x Vi =  Mf x Vf

2.00 x Vi = 0.15 x 100.0

2.00 x Vi = 15

Vi = 15 / 2.00

Vi = 7.5 mL

hope this helps!


3 0
3 years ago
Nvmmmmmmmmmmmmmmmmmmmmmmmmm lol
Vlad1618 [11]

Answer:

coooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooool lol

Explanation:

7 0
3 years ago
Read 2 more answers
A 150.0 mL sample of a 1.50 M solution of CuSO4 is mixed with a 150.0 mL sample of 3.00 M KOH in a coffee cup calorimeter. The t
svp [43]
Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225 
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>

<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
<span>dHrxn in J/mol= q/0.225 mol CuSO4 </span>
<span>Then convert to kJ/mol


</span>
5 0
3 years ago
Read 2 more answers
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