Answer : The correct option is, ![-89.2^oF\text{ and }183.9K](https://tex.z-dn.net/?f=-89.2%5EoF%5Ctext%7B%20and%20%7D183.9K)
Explanation :
The conversion used for the temperature from Fahrenheit to degree Celsius is:
![^oC=(^oF-32)\times \frac{5}{9}](https://tex.z-dn.net/?f=%5EoC%3D%28%5EoF-32%29%5Ctimes%20%5Cfrac%7B5%7D%7B9%7D)
where,
= temperature in Fahrenheit
= temperature in centigrade
The conversion used for the temperature from degree Celsius to Kelvin is:
![K=273.15+^oC](https://tex.z-dn.net/?f=K%3D273.15%2B%5EoC)
where,
= temperature in Kelvin
= temperature in centigrade
As we are given the temperature in Fahrenheit is, -10
Now we have to determine the temperature in degree Celsius.
![^oC=(^oF-32)\times \frac{5}{9}](https://tex.z-dn.net/?f=%5EoC%3D%28%5EoF-32%29%5Ctimes%20%5Cfrac%7B5%7D%7B9%7D)
![^oC=(-128.6^oF-32)\times \frac{5}{9}](https://tex.z-dn.net/?f=%5EoC%3D%28-128.6%5EoF-32%29%5Ctimes%20%5Cfrac%7B5%7D%7B9%7D)
![^oC=-89.2](https://tex.z-dn.net/?f=%5EoC%3D-89.2)
Now we have to determine the temperature in Kelvin.
![K=273.15+^oC](https://tex.z-dn.net/?f=K%3D273.15%2B%5EoC)
![K=273.15+(-89.2^oC)](https://tex.z-dn.net/?f=K%3D273.15%2B%28-89.2%5EoC%29)
![K=183.9](https://tex.z-dn.net/?f=K%3D183.9)
Therefore, the temperature in degree Celsius and Kelvin are, ![-89.2^oF\text{ and }183.9K](https://tex.z-dn.net/?f=-89.2%5EoF%5Ctext%7B%20and%20%7D183.9K)
4.2 L= kl? ,,,,,,,,,,,,,,,
Lunna [17]
4.2 Liters = .0042 Kiloliters
All I know is that Pseudoscience is: A collection of beliefs or practices mistakenly regarded as being based on scientific method.
Hope this helps..
Answer:
<em>hehe I needed some brianliest plz OK </em>
Explanation:
<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>