If two clear aqueous solutions are mixed and a colored precipitate forms, what type

Chemistry

1 answer:

Sveta_85 [38]3 years ago

3 0

Answer:

When two clear aqueous solutions react, they sometimes form solids in the solution. The solid is called a precipitate. Precipitation reactions occur when the cations of one reactant and the anions of a second reactant found in aqueous solutions combine to form an insoluble ionic solid that we call a precipitate.

Explanation:

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You made up a saturated solution of calcium sulfate (CaSO4). The temperature is 25°C. You then add 5.00 × 10−3 M sodium sulfate

BARSIC [14]

Answer:

$Ca^{+2}=5.13x10^{-3}M\\SO_4^{-2}=0.010 M$

Explanation:

Hello,

At first, the answer is wrong, consider the following procedure:

- the pKs, leads to a Ks of:

$pKs=-Log(Ks)$

$Ks=10^{-4.58}=2.63x10^{-5}$

- now, stating the equilibrium for the calcium sulfate (whereas x is the change during the equilibrium):

$Ks=[Ca^{+2}]^{eq}[SO_{4}^{-2}]^{eq}\\Ks=[x]^{eq}[x]^{eq}\\Ks=x^{2}\\x=\sqrt{2.63x10^{-5}}\\x=5.13x10^{-3} M$

- x becomes the concentration of calcium ions and one of the contributions for the total concentration of sulfate ions, thus:

$[Ca^{+2}]^{eq}=5.13x10^{-3} M$

- finally, since the sodium sulfate is totally dissolved, we just simply add its concentration (equal to the sulfate ions yielded by itself) to the outgoing sulfate concentration from the calcium sulfate:

$[SO_4^{-2}]^{total}=5x10^{-3}M+5.13x10^{-3}M\\[SO_4^{-2}]^{total}=0.010 M$

Bibliography:https://books.google.com.co/books?id=LQwyfFc3pXsC&lpg=PA243&ots=zIJN3nSFWE&dq=pKs%20chemistry&pg=PA244#v=onepage&q=pKs%20chemistry&f=false page 243

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Is helium a compound

natita [175]

Answer:no

Explanation:

its a gas jkjk its an element

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