Answer:
4.5 g/L.
Explanation:
- To solve this problem, we must mention Henry's law.
- Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
- It can be expressed as: P = KS,
P is the partial pressure of the gas above the solution.
K is the Henry's law constant,
S is the solubility of the gas.
- At two different pressures, we have two different solubilities of the gas.
<em>∴ P₁S₂ = P₂S₁.</em>
P₁ = 525.0 kPa & S₁ = 10.5 g/L.
P₂ = 225.0 kPa & S₂ = ??? g/L.
∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.
Monoprotic acid are acids having
only one hydrogen atoms after dissociation into ions from its compound. The
monoprotic acid from among the following is HCl. The answer is letter D. HCl →
H+ + Cl-. Note that there is only one H+ ion upon dissociation.
Answer:
Percent error = 5.6%
Explanation:
Given data:
Measured value of density by students = 2.85 g/cm³
Accepted density of aluminium = 2.70 g/cm³
Percent error = ?
Solution:
Formula:
Percent error = [ Measured value - accepted value / accepted value ]× 100
Now we will put the values in formula:
Percent error = [ 2.85 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100
Percent error = [0.15/2.70 g/cm³ ] × 100
Percent error = 0.056× 100
Percent error = 5.6%
