Answer:
a_total = 2 √ (α² + w⁴)
, a_total = 2,236 m
Explanation:
The total acceleration of a body, if we use the Pythagorean theorem is
a_total² = a_T²2 + ²
where
the centripetal acceleration is
a_{c} = v² / r = w r²
tangential acceleration
a_T = dv / dt
angular and linear acceleration are related
a_T = α r
we substitute in the first equation
a_total = √ [(α r)² + (w r² )²]
a_total = 2 √ (α² + w⁴)
Let's find the angular velocity for t = 2 s if we start from rest wo = 0
w = w₀ + α t
w = 0 + 1.0 2
w = 2.0rad / s
we substitute
a_total = r √(1² + 2²) = r √5
a_total = r 2,236
In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m
a_total = 2,236 m
The correct answer is yes, the acceleration can be zero. We know that velocity is the derivative of position and acceleration is the derivative of velocity. Therefore, we are trying to determine if there is any nonzero velocity function that we can take the derivative of to get 0. Any velocity function that is a coefficient such as v(t)=5, would have an acceleration of 0 because the derivative of a constant is always 0.
Hope this helps.
Line - A: (15/10) = 1.5 inch/second
Line - B: (0/10) = 0
Line - C: (10/10) = 1.0 inch/second
Line - D: (-25/20) = -1.25 inch/second
<em>Line-A</em> represents the greatest speed.
Answer:
0
Explanation:
The displacement is zero since it goes in a full circle and ends up where it started.
Answer:
a
b
Explanation:
From the question we are told that
The position of the column of mercury in the barometer is \
The density of mercury is
Generally the pressure of the atmosphere at that column is mathematically represented as
=>
=>
Generally the atmospheric pressure at sea level (Generally the pressure before the change in level of the mercury column) is
Generally the change in air pressure is mathematically represented as
=>
=>
Generally the height which the column will rise to is mathematically evaluated as
Here is the density of water with value
So
=>