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Debora [2.8K]
3 years ago
12

Which arrangement in relative size is correct? (< sign means 'smaller than')

Physics
2 answers:
dusya [7]3 years ago
6 0
The right option is D.
galina1969 [7]3 years ago
3 0

Answer:

D. electron < neutron < atomic nucleus < atom

Explanation:

size of an electron = 2.82 * 10^{-15} m.

size of a neutron = 0.8 * 10^{-15} m.

size of a atomic nucleus = 1.56 *  10^{-14} m.

size of an atom  =  0.1 - 0.5 nanometers

hence if we compare the size of all components we will see size of an electron is the smallest and size of an atom is the largest.

electron < neutron < atomic nucleus < atom

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The weight of a body of certain mass becomes zero in space.why?write with reasons​
Anvisha [2.4K]

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

7 0
3 years ago
What component of an atom determines what element it is?
serg [7]
The number of protons in the element.
8 0
3 years ago
Complete the passage to describe the relationship between kinetic energy, internal energy, thermal energy, and
butalik [34]

Answer:

Increases

Increases

Increases

Explanation:

I don't know if you answered your own question but I'll just answer this for others confused ahh

4 0
2 years ago
Read 2 more answers
A handful of professional skaters have taken a skateboard through an inverted loop in a full pipe. For a typical pipe with a dia
Bingel [31]

Answer

given,

diameter of the pipe is  =  (14 ft)4.27 m

minimum speed of the skater must have at very top = ?

At the topmost point of the pipe the  normal force will be equal to zero.

F = mg

centripetal force acting on the skateboard

F = \dfrac{mv^2}{r}

equating both the force equation

mg = \dfrac{mv^2}{r}

v = \sqrt{gr}

r = d/2 = 14/ 2 = 7 ft

or

r = 4.27/2 = 2.135 m

g = 32 ft/s²   or g = 9.8 m/s²

v = \sqrt{32 \times 7}

v = 14.96 ft/s

or

v = \sqrt{9.8 \times 2.135}

v = 4.57 m/s

5 0
3 years ago
A motorcycle rider moving with an initial velocity of 9.2 m/s uniformly accelerates to a speed of 19.1 m/s in a distance of 32.0
Vlada [557]
Acceleration = (final velocity^2 - initial velocity^2) / 2 * distance

Acceleration = (19.1^2 - 9.2^2) / 2 * 32

Acceleration = (364.81 - 84.64) / 64

Acceleration = 280.17 / 64

Acceleration = 4.3777m/s^2

:)
6 0
3 years ago
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