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Nata [24]
3 years ago
8

Monochromatic light is incident on a grating that is 75 mmwide

Physics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

Explanation:

Given

Grating Width w=75 mm

no of lines N=50,000 lines

inclination of second order maxima \theta =32.5^{\circ}

Condition of maxima For Diffraction grating

d\sin \theta =m\lambda

where d=Grating\ constant

\lambda =wavelength

m=order\ of\ maxima

d=\frac{width}{N}

d=\frac{75}{50,000}

d=0.0015\ mm

therefore for second order maxima wavelength of light is given by

\lambda =\frac{d\sin \theta }{m}

\lambda =\frac{0.0015\times \sin (32.5)}{2}

\lambda =403\times 10^{-6}\ m

\lambda =403\ nm

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Answers:

A) 0.204 m

B) 0.285 s

Explanation:

<h2>Answer A:</h2>

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y=0.204 m (3)  This is the distance at which the fly would begin to beat its wings

<h2>Answer B:</h2>

In this part we will also use equation (1), but we will find the time:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 is the final height of the fly

y_{o}=40 cm=0.4 m is the initial height of the fly

V_{o}=0 is the initial velocity of the fly

t is the time  we need to find

g=9.8 m/s^{2} is the acceleration due to gravity

0=0.4 m+0-\frac{1}{2}(9.8 m/s^{2})t^{2} (4)

Isolating t:

t^{2}=\frac{(-2)(-0.4 m)}{9.8 m/s^{2}} (5)

t=0.285 s (6)  This is the time it would take for a fly to hit the bottom of the box

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