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Nata [24]
2 years ago
8

Monochromatic light is incident on a grating that is 75 mmwide

Physics
1 answer:
statuscvo [17]2 years ago
3 0

Answer:

Explanation:

Given

Grating Width w=75 mm

no of lines N=50,000 lines

inclination of second order maxima \theta =32.5^{\circ}

Condition of maxima For Diffraction grating

d\sin \theta =m\lambda

where d=Grating\ constant

\lambda =wavelength

m=order\ of\ maxima

d=\frac{width}{N}

d=\frac{75}{50,000}

d=0.0015\ mm

therefore for second order maxima wavelength of light is given by

\lambda =\frac{d\sin \theta }{m}

\lambda =\frac{0.0015\times \sin (32.5)}{2}

\lambda =403\times 10^{-6}\ m

\lambda =403\ nm

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pantera1 [17]

Answer:

The period is T =  0.700 \ s

Explanation:

From the question we are told that  

    The mass is m =  0.350  \ kg

     The extension of the spring is  x =  12.0 \ cm = 0.12 \ m

       

The spring constant for this is mathematically represented as

       k  = \frac{F}{x}

Where F is the force on the spring which is mathematically evaluated as

       F  =  mg  =  0.350 * 9.8

       F  =3.43 \ N

So  

    k  = \frac{3.43 }{ 0.12}

    k  = 28.583 \ N/m

The period of oscillation is mathematically evaluated as

      T =  2 \pi \sqrt{\frac{m}{k} }

substituting values

     T =  2  *  3.142*  \sqrt{\frac{0.35 }{28.583} }

     T =  0.700 \ s

   

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3 years ago
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T= \frac{1}{f}= \frac{1}{0.16 Hz}=6.25 s

The period of the pendulum is given by
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where L is the length of the pendulum, and g the acceleration of gravity. By re-arranging the formula and using the value of T we found before, we can  calculate the length of the pendulum L:
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