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2 years ago

10

What is the surface area? Please help. Thanks!

1 answer:

ValentinkaMS [17]2 years ago

7 0

340.8 will be the answer i know how to do surface area of a pyramid but this one is a little confusing i followed the formula and all that but i think this is the right answer, sorry if it was wrong

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Please help I'm not very good at math and i don't really understand what's going on

solniwko [45]

Answer:

The amount left after each friend got $46.

Step-by-step explanation:

Any time you see R1 in bus stop method division, it just means remainder. So dividing 93 dollars between 2 friends gives them both 46 dollars, with one left over!

Hope this helps :)

8 0

2 years ago

What is the common ratio of 17, 51, 153, 459,.....

adelina 88 [10]

Answer:

3

Step-by-step explanation:

17 * 3 = 51

51 * 3 = 153

153 * 3 = 459

etc.

8 0

2 years ago

Read 2 more answers

Please help! Due very soon!

Arada [10]

Answer:

9

6

3

3

6

3

3

multiply

row

18

32

Step-by-step explanation:

The answer to each blank, in order from top to bottom

8 0

3 years ago

What number is 1/8 of 1000

Dmitry_Shevchenko [17]

125 125x8=1000 1/8 of 1000 is 125

5 0

3 years ago

Read 2 more answers

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago