Answer:
Hey there!
The correct answer would be a line from (0, 0) to (-1, 2)
Let me know if this helps :)
Log base b=logb
4 log₂ 2x+ 2logb x=4
log₂(2x)⁴+logb x²=log₂16
log₂ 16x⁴+ logb x²=log₂ 16
logb x²=log₂ 16 - log₂ 16x⁴
logb x²=log₂ (16/16x⁴)
logb x²= log₂ x⁻⁴
logb x²=log₂ x² / log₂ b
log₂ x² / log₂ b=-log x⁴
log₂ b=log₂ x² /- log₂ x⁴
log₂ b=2 log x / -4 log₂ x
log₂ b=-1/2 ⇔ b=2⁻¹/² =1/√2=(√2)/2≈ 0.707106781....
Answer: b=(√2)/2
To chek
if x=10
log base √2/2= log√2/2
4 log₂ 20 + 2log√2/2 10=4(4.321928095...)+2 (-6.64385619=
= 17.28771238-13.28771238=4
Answer:
0.75757575757
Step-by-step explanation:
Answer:
Step-by-step explanation:
its B