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pochemuha
3 years ago
14

Determine if there is a proportional relationship between the two quantities. Explain your reasoning.

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Step-by-step explanation:

If two quantities A and B are proportional, then:

B = kA

where k is a constant.

We can check if these are proportional by seeing if the ratio between A and B is the same at each point:

B/A = k

92/35 = 2.629

80/23 = 3.478

The ratios aren't the same, the relationship is not proportional.

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G * 9 = 3.6 solve for G what is it​
larisa86 [58]
G = 2.5

Use inverse operations. 9 / 3.6 = 2.5.
8 0
3 years ago
Find the surface area of this cube 7m 7m 7m. Be sure to include the correct unit in your answer.
7nadin3 [17]

Answer:

294m^2

Step-by-step explanation:

The area of one face of the cube would be 7 x 7 = 49 m^2

Since there are 6 faces on a cube, the total surface area would therefore be 49 x 6 = 294m^2

4 0
2 years ago
An inverse variation includes the points (15,1) and (n,5). Find n
djyliett [7]
Inverse variation: y=k/x

1. plug in the values: (15,1)
1=k/15

2. solve for k

3. Now, plug in what you can for the second point: (n,5)
5=k/n (if you do the step above, you will know “k”.

4. Solve for “n”


7 0
2 years ago
A metallurgist needs to make 12.4 lb. of an 10) alloy containing 50% gold. He is going to melt and combine one metal that is 60%
sergeinik [125]
Now, let's say, we add "x" lbs of the 60% gold alloy, so..  how much gold is in it?  well, is just 60%, so (60/100) * x, or 0.6x.

likewise, if we use "y" lbs of the 40% alloy, how much gold is in it?  well, 40% of y, or (40/100) * y, or 0.4y.

now, whatever "x" and "y" are, their sum must be 12.4 lbs.

we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.

\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{gold~\%}{quantity}&\stackrel{gold}{quantity}\\
&------&------&------\\
\textit{60\% alloy}&x&0.6&0.6x\\
\textit{40\% alloy}&y&0.4&0.4y\\
------&------&------&------\\
\textit{50\% alloy}&12.4&0.50&6.2
\end{array}

\bf \begin{cases}
x+y=12.4\implies \boxed{y}=12.4-x\\
0.6x+0.4y=6.2\\
-------------\\
0.6x+0.4\left( \boxed{12.4-x} \right)=6.2
\end{cases}
\\\\\\
0.6x-0.4x+4.96=6.2\implies 0.2x=1.24\implies x=\cfrac{1.24}{0.2}
\\\\\\
x=\stackrel{lbs}{6.2}

how much of the 40% alloy?  well, y = 12.4 - x.
5 0
3 years ago
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kow [346]
The difference between Jasons in Kim’s meters ran are 3875
8 0
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