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4 years ago

Can somebody google or pls if u know the correct answer help!!!

Physics

2 answers:

love history [14]4 years ago

8 0

Answer:

Nutrients

Oxygen

Water

Stable body temperature

Atmospheric pressure

Explanation:

Goshia [24]4 years ago

3 0

Answer:

The five basic survival needs are, oxygen, water, food , shelter, and self defense they're important because these things help keep us alive and functioning. These are the bare necessities to living.

Explanation

In order to survive, all living things need air, water, food, shelter, and slef-defense. Animals obtain their food from plants and other animals, which provides them with the energy they need to move and grow. ... Plants also need air, water, and food, but they don't have mouths to breathe, drink or eat.

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A 5.17 kg block free to move on a horizontal, frictionless surface is attached to one end of a light horizontal spring. The othe

Andreyy89

Answer:

v=0.816 m/s

Explanation:

The force of the spring and the motion of the block are in equilibrium so without any force of friction the motion is

$E_{s}=E_{k}$

$\frac{1}{2}*k*d_{s}^2=\frac{1}{2}*m*v^2$

First determinate the constant of the spring that produce the kinetic energy of the bloc

$k=\frac{m*v^2}{d_{s}^2}$

$k=\frac{5.17kg*(1.30\frac{m}{s})^2}{0.102^2m}$

$k=839.8 \frac{kg}{s^2}$

Now the motion with the force of friction in the kinetic

$E_{s}=E_{k}-W_{k}$

$\frac{1}{2}*k*d_{s}^2=\frac{1}{2}*m*v^2-u*m*g$

Resolve to v

$v^2=\frac{(k*d_{s}^2)+(2*g*u)}{m}$

$v=\sqrt{\frac{839.8*(0.102m)^2-2*9.8*0.270}{5.17}}$

$v=0.81 \frac{m}{s}$

3 0

3 years ago

What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force i

CaHeK987 [17]

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ $F_{net}=ma$

$=5\times 1.7$

$=8.5 \ N$

(b)

For m₃,

⇒ $ma=\mu m_3 g$

Or,

⇒ $\mu=\frac{a}{g}$

$=\frac{1.7}{9.8}$

$=0.173$

5 0

3 years ago

An athlete at high performance inhales 4.0L of air at 1 atm and 298 K. The inhaled and exhaled air contain 0.5% and 6.2% by volu

LenaWriter [7]

To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.

An athlete at high performance inhales 4.0L of air at 1atm and 298K.

The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.

During inhalation, volume of water taken is

$V_i = (4L)(0.5\%)$

$V_i = 0.02L$

During exhalation, volume of water expelled is

$V_e = (4L)(6.2\%)$

$V_e = 0.248L$

During 40 breathes, total volume of water taken is

$V_{it} = (40L)(0.02L) = 0.8L$

During 40 breathes, total volume of water expelled out is

$V_{et} = (40L)(0.248L) = 9.92L$

Therefore resultant volume of water expelled out from the lung is

$\Delta V = 9.92L-0.8L = 9.12$

From the body through the lung we have that

$n = \frac{PV}{RT}$

Here,

P = Pressure

R= Gas ideal constant

T= Temperature

V = Volume

Replacing,

$n = \frac{(1atm)(9.12L)}{(8.314J/mol \cdot K)(298K)}$

$n = 0.373mol/min$

Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min

8 0

4 years ago

A projectile is fired straight upward from earths surface with a speed c given by: v^2= GM/2R. Where M is the mass and R is the

Scilla [17]

Answer:

4R/3

Explanation:

r = Distance from the surface of the Earth

R = Radius of Earth

G = Gravitational constant

M = Mass of Earth

m = Mass of satellite

v²= GM/2R

Loss of Kinetic energy is equal to Gain in potential energy

$\frac{1}{2}mv^2=\frac{GMm}{R}-\frac{GMm}{r}\\\Rightarrow \frac{1}{2}m\frac{GM}{2R}=GMm\left(\frac{1}{R}-\frac{1}{r}\right)\\\Rightarrow \frac{1}{2}\frac{1}{2R}=\frac{r-R}{Rr}\\\Rightarrow \frac{1}{4}=\frac{r-R}{r}\\\Rightarrow r=4r-4R\\\Rightarrow -3r=-4R\\\Rightarrow r=\frac{4}{3}R$

∴ The farthest the projectile reaches from the center of the earth is $\mathbf{\frac{4}{3}R}$

6 0

3 years ago

While riding a bicycle, if you stop pedaling you will still continue to move forward due to ______.

adelina 88 [10]

When riding a bicycle, if you stop pedaling you will still continue to move forward due to inerita.

3 0

3 years ago