Answer:
16.5 m
Explanation:
Given,
Magnetic field = 0.02 T
radius of electron = 9 mm
speed of electron = speed of proton
radius of proton = ?
We know,
.........(1)
using newton second law
equating Force due to electron and proton
m_ e = 9.1 x 10⁻³¹ Kg and m_p = 1.67 x 10⁻²⁷ Kg
Hence, the radius of proton is equal to 16.5 m.
Answer:
1.26 secs.
Explanation:
The following data were obtained from the question:
Force (F) = 20 N
Extention (e) = 0.2 m
Mass (m) = 4 Kg
Period (T) =.?
Next, we shall determine the spring constant, K for spring.
The spring constant, K can be obtained as follow:
Force (F) = 20 N
Extention (e) = 0.2 m
Spring constant (K) =..?
F = Ke
20 = K x 0.2
Divide both side by 0.2
K = 20/0.2
K = 100 N/m
Finally, we shall determine the period of oscillation of the 4 kg object suspended on the spring. This can be achieved as follow:
Mass (m) = 4 Kg
Spring constant (K) = 100 N/m
Period (T) =..?
T = 2π√(m/K)
T = 2π√(4/100)
T = 2π x √(0.04)
T = 2π x 0.2
T = 1.26 secs.
Therefore, the period of oscillation of the 4 kg object suspended on the spring is 1.26 secs.
Answer: i guess d is the correct answer
Answer:
because you can get very electrocuted and you could get a disease I never put your hand add water on and touching water cuz you can get your hand electrocuted
Explanation: