First find the time it takes to hit the sand t
using s=1/2 g t^2
t^2= 8/9.8= 0.82 seconds
This means the sand was s = 8 * 0.82 = 6.5m away
The horizontal speed stays constant at 8 m/s
The vertical speed =.82 * 9.8 = 8.0 m/s
As the two velocities are equal the angle must be 45 degrees to the horizontal
Answer:
140Ns
Explanation:
From Newton's 2nd law of motion
F = ma
F = m∆v/t
==> Ft = m∆v
impulse = Ft = 400 × 0.35 = 140Ns
<span>The equilibrium position is that at which the pendulum is at its lowest point; it is called this because, absent any other forces acting upon it, this is the point at which the pendulum would be at a stable, motionless equilibrium. It is also the point at which the pendulum, having been released from above, has translated its starting gravitational potential energy fully into kinetic energy. As such, this means that at this point the pendulum is at its maximum D) velocity.</span>
Answer:
22.658 N
Explanation:
We can consider the Force as a sum of horizontal and vertical force vector components as mentioned in the graph,
Here the θ =25 degrees , F=25
Horizontal force =Fx
cos θ 
Answer:
450 J
5.88235 m/s
Explanation:
The kinetic energy is given by
The kinetic energy of the bullet before it hits the block is 450 J
= Mass of bullet = 0.01 kg
= Mass of block = 0.5 kg
= Initial Velocity of bullet = 300 m/s
= Initial Velocity of second block = 0 m/s
v = Velocity of combined mass
In this system the linear momentum is conserved
The velocity of the bullet+block after the collision is 5.88235 m/s
