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3 years ago

14

Which is a statement that summarizes a pattern found in nature A. A hypothesis B. A scientific law C. A fact D.a scientific theo

ry

2 answers:

krok68 [10]3 years ago

6 0

The answer is B. Scientific Law

dalvyx [7]3 years ago

4 0

The answer is

B: A scientific law

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a hiker walks 200 m west and then walks 100 m north in what direction is her resulting displacement draw to show your answer

Sliva [168]

Answer:

The direction of the displacement is in North-West.

Explanation:

Resultant displacement D is

$=\sqrt{(200)^{2} + (100)^{2} } \\=223.60m$

Here the direction is

$\Theta =tan^{^{-1}}\left ( \frac{100}{200} \right )\\\Theta =26.6^{o}$

Then the direction is $26.6^{o}$ North-west.

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3 years ago

The aqueous humor in a person's eye is exerting a force of 0.242 N on the 1.21 cm2 area of the cornea. What pressure is this in

Virty [35]

Answer:

<h2><em>15.00124mmHg</em></h2>

Explanation:

Pressure is defined as the ratio of force applied to an object to its area.

Pressure = Force/Area

Given parameters

Force = 0.242N

Area = 1.21cm²

Required parameters

Pressure = 0.242/1.21

Pressure = 0.2N/cm²

Using the conversion to convert the pressure to mmHg

1N/cm² = 75.0062mmHg

0.2N/cm² = y

y = 0.2 * 75.0062

y = 15.00124mmHg

<em>Hence the pressure in mmHg is 15.00124mmHg</em>

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3 years ago

Discuss five occasions when people dance

Xelga [282]

Answer:

Party, Birthday, Weddings, Nightclub, Just for fun

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3 years ago

A cat dozes on a stationary merry-go-round, at a radius of 4.4 m from the center of the ride. The operator turns on the ride and

monitta

Answer:

The coefficient of static friction is 0.29

Explanation:

Given that,

Radius of the merry-go-round, r = 4.4 m

The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.

We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.

$\mu mg=\dfrac{mv^2}{r}$

v is the speed of cat, $v=\dfrac{2\pi r}{t}$

$\mu=\dfrac{4\pi^2r}{gt^2}\\\\\mu=\dfrac{4\pi^2\times 4.4}{9.8\times (7.7)^2}\\\\\mu=0.29$

So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.

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3 years ago

PLEASE HELP! Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an

zavuch27 [327]

Answer:

The height of building should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.

Explanation:

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3 years ago