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nlexa [21]
3 years ago
7

A D note has a frequency of 587.33 Hz. Calculate its wavelength in meters.

Physics
2 answers:
Vesna [10]3 years ago
6 0
I think the answer is .579 m
melomori [17]3 years ago
4 0

Answer:

0.584m

Explanation:

Wavelength is defined as the distance between two successive crest and trough of a wave.

Given that the speed (v) of a wave is the product of the frequency (f) of the wave and its wavelength (¶)

i.e v = f¶ where;

¶ = v/f

Given v = 343m/s (velocity of sound in air which is a constant value)

f = 587.33Hz

¶ = 343/587.33

¶ = 0.584m

The wavelength of the wave in meters is 0.584m

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X rays of wavelength 0.0169 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr
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Answer:

a) 4.04*10^-12m

b) 0.0209nm

c) 0.253MeV

Explanation:

The formula for Compton's scattering is given by:

\Delta \lambda=\lambda_f-\lambda_i=\frac{h}{m_oc}(1-cos\theta)

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c) The electron Compton wavelength is 2.43 × 10-12 m. Hence you can use the Broglie's relation to compute the momentum of the electron and then the kinetic energy.

P=\frac{h}{\lambda_e}=\frac{6.62*10^{-34}Js}{2.43*10^{-12}m}=2.72*10^{-22}kgm\\

E_e=\frac{p^2}{2m_e}=\frac{(2.72*10^{-22}kgm)^2}{2(9.1*10^{-31}kg)}=4.06*10^{-14}J\\\\1J=6.242*10^{18}eV\\\\E_e=4.06*10^{-14}(6.242*10^{18}eV)=0.253MeV

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4 years ago
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Given that,

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