Ask question

Ask question

All categories

3 years ago

15

A sled with a mass of 32 kg is being pulled across the snow. If the friction force between the sled and the ground is 12 N, what

is the force needed to accelerate the sled at a rate of 1.1 m/s2?

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

Fa= 47.2N

Explanation:

You might be interested in

Find the mass of a flying discus that has a net force of 1.05 newtons and accelerates at 3.5 m/s^2

Ilya [14]

F=ma
m=1.05/3.5= 0.3kg

8 0

3 years ago

Which car is accelerating?

professor190 [17]

B.)a car that rounds a curve at a constant speed

5 0

3 years ago

Sedaia [141]

Answer:

V = 20.5 m/s

Explanation:

Given,

The mass of the cart, m = 6 Kg

The initial speed of the cart, u = 4 m/s

The acceleration of the cart, a = 0.5 m/s²

The time interval of the cart, t = 30 s

The final velocity of the cart is given by the first equation of motion

v = u + at

= 4 + (0.5 x 30)

= 19 m/s

Hence the final velocity of cart at 30 seconds is, v = 19 m/s

The speed of the cart at the end of 3 seconds

V = 19 + (0.5 x 3)

= 20.5 m/s

Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s

6 0

3 years ago

Describe the relationship between a moving objects mass and its kinetic energy

WINSTONCH [101]

KE = 1/2 mv^2 is the relationship betwee mass and kinetic energy

8 0

3 years ago

A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cr

Musya8 [376]

Answer:

162500000.

Explanation:

Given that

Diameter of the wire , d= 1.8 mm

The length of the wire ,L = 15 cm

Current ,I = 260 m A

The charge on the electron ,e= 1.6 x 10⁻¹⁹ C

We know that Current I is given as

$I=\dfrac{q}{t}$

I=Current

q=Charge

t=time

q= I t

q= 260 m t

The total number of electron = n

q= n e

$n=\dfrac{260\times 10^{-3}\ t}{1.6\times 10^{-9}}$

n=162500000 t

$\dfrac{n}{t}=16250000$

The number of electron passe per second will be 162500000.

4 0

3 years ago