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OleMash [197]
4 years ago
9

James is trying to prove Newton's 2nd law of motion. He tries to move four different objects with different masses, shapes, and

sizes from point A to point B. The objects are a toy car, a car, a refrigerator, and a kitchen table. After some experimentation, he finds that force is dependent on the mass of the object, rather than it's size or shape. The object that takes the most force to move is the
Physics
2 answers:
STatiana [176]4 years ago
8 0

The car is the heaviest object there and mass is proportional to force, meaning the heavier it is the bigger the force should be in order to move it.

meriva4 years ago
8 0

Answer:

A car

Explanation:

Newton’s second law of motion states that the rate of change of linear momentum is directly proportional to the applied unbalanced force. It also gives the measure of force i.e.

F = m.a.... (1)

Where

m is the mass of body

a is the acceleration produced

In this case, James is trying to prove Newton's 2nd law of motion. He moves four object namely, a toy car, a car, a refrigerator, and a kitchen table with different masses, shapes, and sizes from point A to point B.

It is clear from equation (1), that the force depend only on the mass of body not on its shape and size.

So, the force that takes the most force to move is ''a car'' due to its more mass.

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In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5190 km away, and released. It found its wa
Rina8888 [55]

Answer:

The bird's average velocity is 4.00 m/s.

Explanation:

Given that,

Distance = 5190 km

Timet = 15.0\ days = 1.296\times10^{6}\ sec

We need to calculate the bird's average velocity for the return flight

Using formula of average velocity

v_{avg}=\dfrac{d_{i}-d_{f}}{t}

Where, d = position

t = total time

Put the value into the formula

v_{avg}=\dfrac{0-5190\times10^{3}}{1.296\times10^{6}}

v_{avg}=-4.00\ m/s

Negative sign shows the bird is traveling in negative x -axis.

Hence, The bird's average velocity is 4.00 m/s.

5 0
3 years ago
The figure below shows two blocks connected by a string of negligible mass passing over a frictionless pulley. m1 = 7.0 kg and θ
loris [4]
First we assume there is no fiction, this is just a basic assumption of all physics problems. We also assume the rope is massless and does not change length since this problem is significantly more complicated if the rope has a mass or can change length.

For part (a) it asks about a system in equilibrium so we see that m1 is hanging vertically and if the system is in equilibrium then all the forces are constant. So I m1 is 7.0 kg then the force of gravity is

Fg = (7.0 kg) (10 N/kg) = 70 N

Since the forces are balanced there must be 70 N pulling it up. All that force is done by the other mass and transfered through the massless rope.

In this case the force of gravity on m2 is 336.681N (see the attached picture for explanation).

So if the force on m2 is about 337 N then it's mass is

m = (337 N) / (10 N/kg) = 33.7 kg

For part (b) it asks about a system where there are unbalanced forces. If m2 slides down with any acceleration and the rope cannot change length then m1 must be accelerating at the same rate. So if m1 accelerates at .4 m/s^2 then the force is

F = Fg + Fm2
F = 70 N + (7.0 kg) (.4m/s^2) = 70 N + 2.8 N = 72.8 N

So now the process for finding the mass of the other block is the same except instead of using 70 in the equation you use 72.8 N. So the new force is 350.149. So the mass must be equal to

m = (350) / (10 N/kg) = 35 kg

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3 years ago
How can I feel pain when I hit a table with my bare hands (Physics)
Sidana [21]
When your hand hits the table the table will vibrate and your hand will be numb for two to three seconds
6 0
4 years ago
A car moving at a speed of 20 m/s, then accelerates uniformly at until it reaches a speed of What distance does it travel during
Andru [333]
E because you have to drive
6 0
3 years ago
An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration
lana [24]

Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward =  g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward =  g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁  =  9.8 - 3  = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

⇒ Vf² = 53. 125

⇒ Vf= 7.29 m/s

8 0
4 years ago
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