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OleMash [197]
4 years ago
9

James is trying to prove Newton's 2nd law of motion. He tries to move four different objects with different masses, shapes, and

sizes from point A to point B. The objects are a toy car, a car, a refrigerator, and a kitchen table. After some experimentation, he finds that force is dependent on the mass of the object, rather than it's size or shape. The object that takes the most force to move is the
Physics
2 answers:
STatiana [176]4 years ago
8 0

The car is the heaviest object there and mass is proportional to force, meaning the heavier it is the bigger the force should be in order to move it.

meriva4 years ago
8 0

Answer:

A car

Explanation:

Newton’s second law of motion states that the rate of change of linear momentum is directly proportional to the applied unbalanced force. It also gives the measure of force i.e.

F = m.a.... (1)

Where

m is the mass of body

a is the acceleration produced

In this case, James is trying to prove Newton's 2nd law of motion. He moves four object namely, a toy car, a car, a refrigerator, and a kitchen table with different masses, shapes, and sizes from point A to point B.

It is clear from equation (1), that the force depend only on the mass of body not on its shape and size.

So, the force that takes the most force to move is ''a car'' due to its more mass.

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M84, M87, and NGC 4258 all have accretion disks around their central black holes for which the rotational velocities have been m
givi [52]

Answer:

<u>For M84:</u>

M = 590.7 * 10³⁶ kg

<u>For M87:</u>

M = 2307.46 * 10³⁶ kg

Explanation:

1 parsec, pc  = 3.08 * 10¹⁶ m

The equation of the orbit speed can be used to calculate the doppler velocity:

v = \sqrt{\frac{GM}{r} }

making m the subject of the formula in the equation above to calculate the mass of the black hole:

M = \frac{v^{2} r}{G}.............(1)

<u>For M84:</u>

r = 8 pc = 8 * 3.08 * 10¹⁶

r = 24.64 * 10¹⁶ m

v = 400 km/s = 4 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

M = \frac{( 4*10^{5}) ^{2} *24.64* 10^{16} }{6.674 * 10^{-11} }

M = 590.7 * 10³⁶ kg

<u>For M87:</u>

r = 20 pc = 20 * 3.08 * 10¹⁶

r = 61.6* 10¹⁶ m

v = 500 km/s = 5 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

M = \frac{( 5*10^{5}) ^{2} *61.6* 10^{16} }{6.674 * 10^{-11} }

M = 2307.46 * 10³⁶ kg

The mass of the black hole in the galaxies is measured using the doppler shift.

The assumption made is that the intrinsic velocity dispersion is needed to match the line widths that are observed.

3 0
3 years ago
6.
S_A_V [24]

The distance in meters she would have moved before she begins to slow down is 11.25 m

<h3>LINEAR MOTION</h3>

A straight line movement is known as linear motion

Given that Ann is driving down a street at 15 m/s. Suddenly a child runs into the street. It takes Ann 0.75 seconds to react and apply the brakes.

To know how many meters will she have moved before she begins to slow down, we need to first list all the given parameters.

  • speed = 15 m/s
  • time t = 0.75 s

From definition of speed,

speed = distance / time

Make distance the subject of the formula

distance = speed x time

distance = 15 x 0.75

distance = 11.25m

Therefore, the distance in meters she would have moved before she begins to slow down is 11.25 m

Learn more about Linear motion here: brainly.com/question/13665920

4 0
2 years ago
Explain how polarization of a cell increases the cell's internal resistance.<br>(2<br>2.​
Mandarinka [93]

Answer:

Explanation: The chemical action that occurs in the cell while the current is flowing causes hydrogen bubbles to form on the surface of the anode. This action is called POLARIZATION. Some hydrogen bubbles rise to the surface of the electrolyte and escape into the air, some remain on the surface of the anode. If enough bubbles remain around the anode, the bubbles form a barrier that increases internal resistance. When the internal resistance of the cell increases, the output current is decreased and the voltage of the cell also decreases.

   A cell that is heavily polarized has no useful output. There are several methods to prevent polarization or to depolarize the cell.

   One method uses a vent on the cell to permit the hydrogen to escape into the air. A disadvantage of this method is that hydrogen is not available to reform into the electrolyte during recharging. This problem is solved by adding water to the electrolyte, such as in an automobile battery. A second method is to use material that is rich in oxygen, such as manganese dioxide, which supplies free oxygen to combine with the hydrogen and form water.

   A third method is to use a material that will absorb the hydrogen, such as calcium. The calcium releases hydrogen during the charging process. All three methods remove enough hydrogen so that the cell is practically free from polarization.

LOCAL ACTION

   When the external circuit is removed, the current ceases to flow, and, theoretically, all chemical action within the cell stops. However, commercial zinc contains many impurities, such as iron, carbon, lead, and arsenic. These impurities form many small electrical cells within the zinc electrode in which current flows between the zinc and its impurities. Thus, the chemical action continues even though the cell itself is not connected to a load.

   Local action may be prevented by using pure zinc (which is not practical), by coating the zinc with mercury, or by adding a small percentage of mercury to the zinc during the manufacturing process. The treatment of the zinc with mercury is called amalgamating (mixing) the zinc. Since mercury is many times heavier than an equal volume of water, small particles of impurities weighing less than mercury will float to the surface of the mercury. The removal of these impurities from the zinc prevents local action. The mercury is not readily acted upon by the acid. When the cell is delivering current to a load, the mercury continues to act on the impurities in the zinc. This causes the impurities to leave the surface of the zinc electrode and float to the surface of the mercury. This process greatly increases the storage life of the cell.

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3 years ago
Help will mark brain list
Hatshy [7]
A jagged line represents a resistor .
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2 years ago
What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from
Bas_tet [7]

Answer:

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Explanation:

7 0
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