To solve this problem, let us all convert the mass of
each element into number of moles using the formula:
moles = mass / molar mass
Where,
molar mass K = 39.10 g / mol
<span>molar mass Cl = 35.45 g / mol</span>
molar mass O = 16 g / mol
<span>and mass O = 13 g – 4.15 g
– 3.76 g = 5.09 g</span>
moles K = 4.15
g / (39.10 g / mol) = 0.106 mol
<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>
moles O = 5.09 g / (16 g /
mol) = 0.318 mol
The ratio becomes:
0.106 K: 0.106 Cl: 0.318 O
We divide all numbers with
the smallest number, in this case 0.106. This becomes:
K: Cl: 3O
Therefore the empirical formula
is:
no because the substance might be harmful
We subtract the enthalpies of the reactants from that of the products:
Since this is < 0, this is an exothermic reaction.
Answer:
BAMMM
Explanation:
A practical application of this colligative property is automotive antifreeze. The freezing point of a 50/50 solution of ethylene glycol (CH 2(OH)CH 2(OH)) is -33 degrees Celsius (-27.4 degrees Fahrenheit), compared with 0 degrees Celsius (32 degrees Fahrenheit).
Answer:
0.19 mol H₂O
General Formulas and Concepts:
<u>Chem</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
Given: 3.5 g H₂O from RxN
<u>Step 2: Define conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
<u /> = 0.194229 mol H₂O
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
0.194229 mol H₂O ≈ 0.19 mol H₂O