Answer:
n = 11.45 mol
Explanation:
Given data:
Number of moles = ?
Volume of gas = 98 L
Pressure = 2.8 atm
temperature = 292 K
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
2.8 atm × 98 L = n × 0.0821 atm.L/ mol.K × 292 K
274.4 atm.L = n × 23.97atm.L/ mol
n = 274.4 atm.L /23.97atm.L/ mol
n = 11.45 mol
Answer:
Highest boiling point - 0.43 m Urea
Second highest boiling point - 0.20 m NiSO4
Third highest boiling point - 0.19 m NH4I
Lowest boiling point - 0.17 m NH4NO3
Explanation:
We know that;
ΔT = kb m i
Where;
ΔT = boiling point elevation
kb = boiling point constant
m = molality of the solution
i = Van't Hoff factor
For NiSO4 , NH4I and NH4NO3 , the Van't Hoff factor, i = 2
But for Urea, the Van't Hoff factor, i = 1
We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.
This facts above account for the arrangement of substances shown in the answer.
Answer:
a. The rate constant = 0.0000030s^-1
b. The half life = 32000secs
Explanation:Please see attachment for explanation
Answer:
• The closing of the frontier
Explanation:
• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier• The closing of the frontier