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Lera25 [3.4K]
3 years ago
7

What is the factored form of 4x^2 + 23x – 72?

Mathematics
1 answer:
fomenos3 years ago
7 0
The correct answer is the last one. (4x-9) (x+8).
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What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
3 years ago
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con
marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force F applied to an object with mass m is directly proportional to its acceleration a:

F=ma (1)

If we isolate a:

a=\frac{F}{m} (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

m_{1}=4 kg

a_{1}=5 m/s^{2}

F=m_{1}a_{1} (3)

F=(4 kg)(5 m/s^{2) (4)

F=20 N (5)

If we apply this same force calulated in (4) in another object with an acceleration of a_{2}=2 m/s^{2}, its mass m_{2} will be:

F=m_{2}a_{2} (6)

20 N=m_{2}2 m/s^{2} (7)

Finding  m_{2}:

m_{2}=10 kg This is the mass of the object

4 0
3 years ago
Write an inequality and solve the problem the sum of a number and 19 is at least 8.2.
Sunny_sXe [5.5K]
When you write it as an inequality you get x + 19 ≈ 8.2 and when you solve it it should look like x + 19 ≈ 8.2
                             19 ≈ - <u>19
</u>                               x ≈ -10.8<u>
</u>
4 0
3 years ago
What is the factored form of 6x^2 + 13x + 6?
LekaFEV [45]

Answer:

(3x+2)(2x+3)

Step-by-step explanation:

6x2+13x+6

6x2+13x+6

=(3x+2)(2x+3)

7 0
3 years ago
Membership at the Universal Fitness Gym offers yearly memberships for $275. Yoga classes cost an additional $5 per class. Write
Dmitry [639]

total cost = membership +cost per class* number of classes

y = 275+5*x

Choice C

6 0
3 years ago
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