1. H₂SO₄ + 2NH₄OH ⟶ (NH₄)₂SO₄ + 2H₂O
2. 2NaOH + H₂CO₃ ⟶ Na₂CO₃ + 2H₂O
3. HNO₃ + KOH ⟶ KNO₃ + H₂O
<em>Explanation</em>:
Acid + base ⟶ salt + water
Take the H from the acid and the OH from the base to get water.
Then, join what’s left to get the salt. Write the symbol for the metal first.
For example, in equation 3, take the H from HNO₃ and the OH from KOH.
Combining the remaining parts (NO₃ and K) to get the salt, KNO₃.
Answer:
See explanation
Explanation:
The question is incomplete but i will try to give you all the necessary guide that you need in order to answer the question.
When compounds are formed, atoms exchange valency. The valency of nitrogen is three while that of the metal is two. The exchange yields M3N2.
If the compound has been specifically mentioned to be a metal, then it must be a group two element. It could be any of Mg, Ca, Sr, Ba or Ra. I did not mention Be here because most of its compounds are covalent.
This will help you to answer the complete question.
Super saturated solution is formed.
<u>Explanation:</u>
Solubility is the property of any substance's capacity, that is the solute of the substance is dissolved in the given solvent to form the solution. We have three different types of solution, unsaturated, saturated and supersaturated solution.
- Unsaturated solution is a solution with lesser amount of solute than its solubility at equilibrium.
- Saturated solution is a solution with the maximum solute dissolved in the solvent.
- Super saturated solution is a solution with more solute than it is required.
The solubility of KI at 30°C is 153 g / 100 ml. Here 180 g of KI in 100 ml of water at 30°C is given, which has more solute than required, so it is super saturated solution.
It is lead (ll) iodide or just lead iodide
