Answer:
Final temperature of calorimeter is 25.36^{0}\textrm{C}
Explanation:
Molar mass of anethole = 148.2 g/mol
So, 0.840 g of anethole =
of anethole = 0.00567 moles of anethole
1 mol of anethole releases 5539 kJ of heat upon combustion
So, 0.00567 moles of anethole release
of heat or 31.41 kJ of heat
6.60 kJ of heat increases
temperature of calorimeter.
So, 31.41 kJ of heat increases
or
temperature of calorimeter
So, the final temperature of calorimeter = 
The correct answer is high temperature solids
Answer:
The correct answer is "Fragment B likely has a higher Guanosine/Citosine content".
Explanation:
Guanosine/Citosine content, or GC content, refers to how many molecules of guanosine and citosine have a DNA fragment, respect to the content of adenine and thymine. The higher the GC content, the higher the temperature needed to denature the fragment of DNA. This happens because guanosine and citosine establish three hydrogen bonds, while adenine and thymine establish two hydrogen bonds when they bind together. Therefore, if fragment A and B are the same length, but at 89 C only fragment A is completely denatured, fragment B likely has a higher GC content.
Answer:
2p
Explanation:
To solve this question, we can use Boyle's Law, which states that:
"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically:

where
p is the pressure of the gas
V is its volume
The equation can be rewritten as

where in this problem we have:
is the initial pressure of the Xe(g) gas
is the initial volume of the Xe(g) gas
is the final volume of the Xe(g) gas
Solving for p2, we find the final pressure of the gas:

So, the final pressure is twice the initial pressure.
It could be a liquid, solid, or gas! Liquid being water, Solid being wood, gas being oxygen. Some examples.<span />