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2 years ago

Name the following ketone: B. 3-hexanone A. 2-heptanone O

Chemistry

1 answer:

djverab [1.8K]2 years ago

4 0

Answer:

Correct answer is option B ( 3-hexanone )...hope this helps:)

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A certain hydrocarbon has a molecular formula of C9H16. Which of the following is not a structural possibility for this hydrocar

snow_tiger [21]

Answer: Option (d) is the correct answer.

Explanation:

It is given that molecular formula is $C_{9}H_{16}$ . Now, we will calculate the degree of unsaturation as follows.

Degree of unsaturation = $C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1$

= $9 - \frac{16}{2} + 1$

= 9 - 8 + 1

= 2

As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.

Yes, this compound could be an alkyne as for alkyne D.B.E = 2.

But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.

Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.

6 0

4 years ago

The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?

Phoenix [80]

To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:
mass moles
C 56.79 4.73
H 6.56 6.50
O 28.37 1.77
N 8.28 0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

 moles ratio
C 4.73 / 0.59 8
H 6.50 / 0.59 11
O 1.77 / 0.59 3
N 0.59 / 0.59 1

The empirical formula would be C8H11O3N.

8 0

3 years ago

(Hurry ASAP!!!) There are 1.5 moles of methane (CH4) in a tank. It has a pressure of 4.4 atm at 173°C. Find the volume occupied

slamgirl [31]

Answer:

hope this help !

Explanation:

Use the given functions to set up and simplify 173 ° C .

1.5 =

CH4 = CH4

4.4 = CH4

173 ° C = CH4

8 0

3 years ago

Which of the following is not harmed by acid rain?

Paul [167]

B) Glass Windows..... Hope it helps :)

7 0

4 years ago

Read 2 more answers

Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is r

iren [92.7K]

Answer:

We need 50.6 grams of oxygen

Explanation:

Step 1: Data given

Mass of ethane = 13.6 grams

Molar mass of ethane = 30.07 g/mol

Step 2: The balanced equation

2C2H6 + 7O2 → 4CO2 + 6H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 13.6 grams / 30.07 g/mol

Moles ethane = 0.452 moles

Step 4: Calculate moles oxygen

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

Step 5: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 1.582 moles * 32.0 g/mol

Mass O2 = 50.6 grams

We need 50.6 grams of oxygen

7 0

3 years ago