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Marina CMI [18]
3 years ago
7

You heat 51 grams of magnesium over a Bunsen burner for several minutes until it reacts with oxygen in the air. Then you weigh t

he resulting product and see that it is now 53 grams. How does this happen without breaking the Law of Conservation of Mass?
Chemistry
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

    The mass was there all along, it was just in the air. The weight of the oxygen from the air is not weighed in the beginning, only at the end as part of the product, making it seem like there is a total mass change.

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Calcula la cantidad de gramos que hay en 12,5 mol de NaCl (Masa Na: 23,0; Cl: 35,5).
Anon25 [30]

Answer:

731.25 g

Explanation:

The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;

Molar mass of sodium chloride= 23.0 + 35.5 = 58.5 gmol-1

From the formula;

Number of moles (n) = mass /molar mass

Number of moles of sodium chloride= 12.5 moles

Mass of sodium = The unknown

Molar mass of sodium chloride= 58.5gmol-1

Mass of sodium chloride= number of moles × molar mass

Mass of sodium chloride= 12.5 × 58.5

Mass of sodium chloride= 731.25 g

4 0
3 years ago
Can I have a gamergirl
Tom [10]

Answer:

no

Explanation:

3 0
3 years ago
Read 2 more answers
Cl2(aq) + H2O H+(aq) + Cl–(aq) + HOCl(aq)
dimulka [17.4K]
44. (a) N2O3 (b) SF4 (c) AlCl3 (d) Li2CO3 46. H Br δ+ δ− 48. The metallic potassium atoms lose one electron and form +1 cations, and the nonmetallic fluorine atoms gain one electron and form –1 anions. K → K+ + e– 19p/19e– 19p/18e– F + e– → F– 9p/9e– 9p/10e– The ionic bonds are the attractions between K+ cations and F– anions. 50. See Figure 3.6. 52. (a) covalent…nonmetal-nonmetal (b) ionic…metal-nonmetal 54. (a) all nonmetallic atoms - molecular (b) metal-nonmetal - ionic 56. (a) 7 (b) 4 58. Each of the following answers is based on the assumption that nonmetallic atoms tend to form covalent bonds in order to get an octet (8) of electrons around each atom, like the very stable noble gases (other than helium). Covalent bonds (represented by lines in Lewis structures) and lone pairs each contribute two electrons to the octet. (a) oxygen, O If oxygen atoms form two covalent bonds, they will have an octet of electrons around them. Water is an example: H O H (b) fluorine, F If fluorine atoms form one covalent bond, they will have an octet of electrons around them. Hydrogen fluoride, HF, is an example: H F (c) carbon, C If carbon atoms form four covalent bonds, they will have an octet of electrons around them. Methane, CH4, is an example: H H H H C (d) phosphorus, P If phosphorus atoms form three covalent bonds, they will have an octet 
6 0
3 years ago
(01.05 LC)
wel

Answer:

it is A trust me I know thank you

7 0
1 year ago
Read 2 more answers
How many grams of NH3 are needed to provide the same number of molecules as in 0.85 grams of SF6?
solniwko [45]

Above it says the molecular weights are

NH3- 17g/mol and SF6-146 g/mol

Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.


<span><span><span>= 1mole / </span><span>146.048g *</span></span> 0.85g</span>


so we would need 0.00582000438 moles of NH3 to have the same number of molecules.

One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:


<span><span><span>= 17.030519999989988 g / </span><span>mole * </span></span>0.00582000438moles</span>


that equals 0.09911770099 grams.

so 0.09911770099 grams is the answer if you round that you get about 0.1 grams


3 0
3 years ago
Read 2 more answers
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