The correct electronic configuration of vanadium 23 is
1s^22s^22p^63s^23p^64s^23d^3
This electronic configuration is correct because it obeys the Aufbau principle which state that electrons fill the atomic orbital of the lowest energy before occupying the higher level. S orbital can occupy a total of 2 electrons, p orbital can occupy a total of 6 electrons while d orbital can occupy a total of 10 electrons. in the electronic configuration above an s orbital is filled before p orbital while the p orbital is filled before the d orbital .
A semiconductor conducts electricity at high temperatures, but not at low temperatures. At high temperatures, metalloids act like metals and conduct electricity.
Explanation:
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6a. physical reaction
6b. endothermic reaction
7a. physical reaction
7b. the reactants are carbon dioxide, water and light energy. the product is starch
7c. exothermic reaction
The one with the highest pH would be a solution with 100 mL of water and also 20 mL of 0.1 M NaOH is added. Solutions without buffers would have the highest pH since the resistance to change is very low. Hope this answers the question.
These could all go either way, hardness and other special properties are what I'm guessing would be the most accurate in determining the kind of material.
luster, cleavage, streak, and color can all be affected by other factors. but I guess cleavage would also be accurate. so I guess hardness special properties and cleavage would be the most reliable.
