<span>Easiest way is to flip the divisor and multply.
4/9 divided by 1/3
is the same as 4/9 times 3/1
Should be pretty easy to go the rest of the way yourself.</span>
Answer:
Option (B)
Step-by-step explanation:
There are two lines on the graph representing the system of equations.
First line passes through two points (-3, 1) and (-2, 3).
Slope of the line = ![\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
= ![\frac{3-1}{-2+3}](https://tex.z-dn.net/?f=%5Cfrac%7B3-1%7D%7B-2%2B3%7D)
m = 2
Equation of the line passing through (x', y') and slope = m is,
y - y' = m(x - x')
Equation of the line passing through (-3, 1) and slope = 2 will be,
y - 1 = 2(x + 3)
y = 2x + 7 ----------(1)
Second line passes through (0, 1) and (-1, 4) and y-intercept 'b' of the line is 1.
Let the equation of this line is,
y = mx + b
Slope 'm' = ![\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
= ![\frac{4-1}{-1-0}](https://tex.z-dn.net/?f=%5Cfrac%7B4-1%7D%7B-1-0%7D)
= -3
Here 'b' = 1
Therefore, equation of the line will be,
y = -3x + 1 ---------(2)
From equation (1) and (2),
2x + 7 = -3x + 1
5x = -6
x = ![-\frac{6}{5}](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B5%7D)
x = ![-1\frac{1}{5}](https://tex.z-dn.net/?f=-1%5Cfrac%7B1%7D%7B5%7D)
From equation (1),
y = 2x + 7
y = ![-\frac{12}{5}+7](https://tex.z-dn.net/?f=-%5Cfrac%7B12%7D%7B5%7D%2B7)
= ![\frac{-12+35}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-12%2B35%7D%7B5%7D)
= ![\frac{23}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B23%7D%7B5%7D)
= ![4\frac{3}{5}](https://tex.z-dn.net/?f=4%5Cfrac%7B3%7D%7B5%7D)
Therefore, exact solution of the system of equations is
.
Option (B) will be the answer.
Answer:
Option 3
Step-by-step explanation:
Given data set is,
{(1.5, 1), (2.5, 3), (3, 3), (3, 5), (3.5, 5), (4.5, 7), (5, 7), (5, 9), (5.5, 9), (6.5, 11), (7.5, 13)}
By using linear regression calculator,
Equation of the linear function will be,
y = 2x - 2
Therefore, Option 3 will be the correct option.
Answer:
0.315 per lb
Step-by-step explanation: