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iris [78.8K]
4 years ago
14

~Use the graph to answer the questions

Chemistry
2 answers:
aniked [119]4 years ago
8 0

Answer:

the number of bacteria will double  and 32

Explanation:

because in 1 hour its 2 and in 2 hours its 4 so it doubled or you can check in 3 hours it was 8 and in 4 hours it was 16 so it doubled. And when you double 16 do find the amount in 5 hours it is 32.

lesantik [10]4 years ago
6 0

Answer:

the answer above is correct

Explanation:

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1) If you have 2.6 moles of iron (III) oxide, how many molecules of iron (III)
Ugo [173]

Answer:

234

Explanation:

so 3 x 3 x 26 =234

8 0
3 years ago
What is one energy transformation that is taking place in the photo?
Galina-37 [17]

I'm guessing the photo means photosynthesis. In that case, it is solar energy to chemical energy. Radiant energy and solar energy is kind of the same thing, so 4th answer.

4 0
3 years ago
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What kind of intermolecular force is between hydrogen sulfide and hydrogen iodide?
RUDIKE [14]
I will have to go with carbon monoxide
8 0
3 years ago
A chemistry student needs 55.0g of carbon tetrachloride for an experiment. by consulting the crc handbook of chemistry and physi
Monica [59]

The volume of a substance is simply the ratio of mass and density. Therefore:

volume = mass / density

 

Calculating for volume of Carbon Tetrachloride that the student has to pour out:

volume = 55.0 g / (1.59 g / cm^3)

<span>volume = 34.60 cm^3</span>

6 0
3 years ago
Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

4 0
3 years ago
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