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Tresset [83]
3 years ago
14

Why did a drop of water need to be added in order to initiate the reaction?

Chemistry
2 answers:
jeka57 [31]3 years ago
5 0

D.because the water is needed to wet the sand and keep the reaction safe

Rufina [12.5K]3 years ago
3 0
I think it’s D . If that’s not it I’m sry I tried lol
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you are heating a solution and recording its temperature every 2 min during an experiment. which is your independent variable an
Zepler [3.9K]
An independent variable is the variable you are changing in order to measure the dependent variable, which is what you are measuring.

In this example, the

independent variable: chemicals in solution
dependent variable: temperature of solution
7 0
3 years ago
PLEASE HURRY! What is the relationship between distance and magnetic attraction? Give me some examples please. Pictures needed.
Sholpan [36]
Magnetism is inversely proportional to distance
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6 0
3 years ago
Consider the following reversible reaction.
Marina86 [1]

Answer:

B is the correct option

Explanation:

K= the ratio of product of concentration of products to the product of concentration of reactants raised to power equal to their cofficients.

7 0
3 years ago
Read 2 more answers
Which of the following is/are true concerning a chemical reaction at equilibrium? 1. The system will be a mixture of reactant an
maks197457 [2]

Answer: Option (e) is the correct answer.

Explanation:

An equilibrium reaction is defined as the reaction where rate of forward reaction will be equal to the rate of backward reaction.

For example, N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g)

So, here amount of reactants that is, nitrogen gas and hydrogen gas  will be constant along with constant amount of formation of product that is, ammonia here.

In an equilibrium reaction there is presence of both reactants and products and hence, both reactants and products constitute the system.

Thus, we can conclude that all the given statements are true.

5 0
3 years ago
How many grams of air are required to complete the combustion of 120 g of phosphorous to diphosphorous pentoxide, assuming the a
DiKsa [7]

Answer:

Explanation:

522 g

Explanation:

Your starting point here will be the balanced chemical equation for this combustion reaction

4

P

(s]

+

5

O

2(g]

→

2

P

2

O

5(s]

Notice that you have a

4

:

5

mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need

5

4

time more moles of oxygen gas.

Use phosphorus' molar mass to determine how many moles you have in that

93.0-g

sample

93.0

g

⋅

1mole P

30.974

g

=

3.0025 moles P

Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction

3.0025

moles P

⋅

5

moles O

2

4

moles P

=

3.753 moles O

2

7 0
3 years ago
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