Answer:
1. Yes
2.The solubility of X is 34.55g/L
Explanation:
Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm
or 1 Litre of water.
From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved
= 0.019kg*1000 = 19g.
if 19g is required to saturate 550mL at 30°C,
then
will saturate 1L
= 34.545g will saturate 1Litre
The solubility thus is 34.55g/L
99.9224 % of the acid is not ionized.
____HA + H₂O ⇌ A⁻ + H₃O⁺
I: ___<em>c</em> ________0 ____0
C: _-α<em>c</em> _______+α<em>c</em> __+α<em>c
</em>
E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c
</em>
pH = 4.110
[H₃O⁺] = α<em>c</em> = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L
α = 7.76 × 10⁻⁵
1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %
The symbol %v/v means percent by volume. Assuming there is no volume effects when these substances are mixed, we calculate as follows:
% v/v = (25 mL ethanol / 25 mL + 150 mL ) x 100
%v/v = 14.29 mL ethanol / mL solution
Hope this answers the question.
Answer:
<h2>
total no. of electron present in Valency shell is called valency electron </h2><h2>___________________</h2>
<h2>valency shell is that in which last electron is present</h2>
