I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is 
Another possible answer is 
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
Its
C. Draw a line connecting the the intersection of the arcs below and above the segment.
Answer:
2) Equation 1 and Equation 2 have the same number of solutions.
Step-by-step explanation:
The two given equations are
1) 15x + 6 = 41 and 2) 2x + 13 = 28
Solving both equations, we get
Solving (1) : 15x + 6 = 41 ⇒ 15x = 41 - 6 = 35
or, x = 35/15 ⇒ x = 7/3
Solving (2) : 2x + 13 = 28⇒ 2x = 28 - 13 = 15
or, x = 15/2 ⇒ x = 15/2
So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.
Answer:
-0.4 should be in between 0 and -0.5, however be as close to -0.5 as possible while not being ON -0.5.
3 4/5 should be in between 3 and 4, so you can split 4/5 into 8/10 which are equal to each other. Then you can pretend to split the 3 and 4 gap into 10 equal pieces. After you split the gap, count 8 parts to the left of 3.
Step-by-step explanation:
I hope you understand what I mean.
