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Sliva [168]
3 years ago
13

Determine the oh of a solution that is 0.220 m in hco3

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

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6 0
2 years ago
Elements make up all things. What is it called
madam [21]

Answer:

Matter

Explanation:

All matter is made up of substances called elements

3 0
3 years ago
What is the volume of 45.6g of silver if the density of silver is 10.5g/mL? A. 4.34mL B. 479mL C. 0.23mL
nirvana33 [79]

Explanation:

first you get moles of silver

n=m/M

hence you add no of moles to this equation

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8 0
3 years ago
Your teacher asks you to design an experiment that shows how plants respond to changes in their environment. You have two identi
tia_tia [17]

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

To test the hypothesis, experiments are performed. This is the experiment.

4. Analyze the results, and make a conclusion.

Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

5. Test or modify.

If you observe no change, repeat the experiment with different colors of light bulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the light bulb contributes to the change.

If our hypothesis does not come out to be true, then another hypothesis can be generated and tests be done for it.

6 0
3 years ago
Read 2 more answers
(a)-Use Lewis symbol store present there action that occurs between Ca and F atoms. (b)-What is the chemical formula of the most
Charra [1.4K]

Answer:

(a) The Lewis structure is shown in the image below.

(b) CaF_2

(c) Calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond.

(d) Calcium atom loses electrons.

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Fluorine is the element of group 17 and second period. The electronic configuration of the element fluorine is - 2, 7 or  1s^22s^22p^5

There is 1 valence electron of fluorine.

The Lewis structure is drawn in such a way that the octet of each atom is complete.  

Thus, calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.

Thus, the formula of calcium chloride is CaF_2.

<u>(a) The Lewis structure is shown in the image below.</u>

<u>(b) CaF_2</u>

<u>(c) Calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond.</u>

<u>(d) Calcium atom loses electrons.</u>

5 0
2 years ago
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