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Lady bird [3.3K]
3 years ago
11

WHAT CAUSES THE MOVEMENT OF THESE AIR PARTICLES IN SOUND WAVES?

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
A vibrating string can create longitudinal waves as depicted in the animation below.



The answer is C) vibrations
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How much water will be required to dissolve 0.3g of benzoic acid at 95oC given that the solubility of BA at 95oC is 68.0g/L?
Ainat [17]
Write as a proportion, showing the relationship of both given information:
68.0g 0.3g
---------- = -----------
1L x ( your answer)

Cross multiply: 68.0g× X = 0.3g × 1L
68.0g (X)= 0.3g/L
Solve for X by dividing both sides by 68.0 g
68.0g (X) = 0.3g/L
------------- ------------------
68.0g 68.0g

Then enter into calculator 0.3/68 and that will be your solution. Make sure you round up.
6 0
3 years ago
Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl The CCl4 formed in the first st
Nadusha1986 [10]

Answer:

n(HCl)=1.96 mol

Explanation:

CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

With ideal yields we will end up with 4 moles of HCl.

With 70% yields on every stage

n(HCl)=0.7*0.7*4=1.96 mol

8 0
3 years ago
Na + Cl --> NaCl
dalvyx [7]

Answer:

38.152 g NaCl would be produced.

Explanation:

\frac{(23 + 35.5) \times 15}{23}  \\  = 38.152 \:  \: g

<u>M</u><u>a</u><u>r</u><u>k</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>Brainliest</u><u> </u>

5 0
3 years ago
Read 2 more answers
G(1)=0 g(n) =g(n-1)+n g(2)=
Aliun [14]
G(2)=2

For this, you can plug in 2 everywhere you see an n. So the equation will read:
g(2)=g(2-1)+2 -> g(2)=g(1)+2. Since we are given g(1)=0, we can plug in 0 where we see g(1). The equation is now. g(2)=0+2. So, g(2)=2.
6 0
3 years ago
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to
AlekseyPX

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength 6.32x10^{-36}m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

\lambda =\frac{h}{m*v}

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m

Best regards!

7 0
3 years ago
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