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Luden [163]
3 years ago
13

Maple syrup which comes from the sap of maple trees contains water and natural sugars its clear brown liquid and the sugar cant

be separated by filtration. under which category will you classify it?
Chemistry
1 answer:
ExtremeBDS [4]3 years ago
8 0
Maple syrup is a homogeneous mixture, because it's uniform in composition (sugar is uniformly dissolved in water). Homogeneous mixture can be separated by<span> taking advantage of the different properties of the individual components such as distillation, but not by filtration.</span>
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Consider the following gas phase reaction:
snow_tiger [21]

Answer:

2NO(g) + O2(g) --> 2NO2(g)

now 400 ml of NO × 2 mol of NO2/2 mol of NO

= 400 ml of NO2

now 500 ml of O2 × 2 mol of NO2/1 mol of O2

= 1000 ml of NO2

now 400 ml of NO2 × 1 mol of O2/2 mol of NO

= 200 ml

subtract that from 500 ml of total i.e. 500-200 =300 ml

The total volume of the reaction mixture is 1000 ml -300ml = 700 ml

6 0
2 years ago
How many electrons can occupy an orbital
8_murik_8 [283]

Answer:

2 electrons

Explanation:

There are five 3d orbitals, each of which can hold up to 2 electrons, for 10 total electrons. An orbital is described by the principle quantum number, n, the angular momentum quantum number, l, and the magnetic quantum number, ml.

3 0
2 years ago
What changes occur in O + O = O2
ozzi

Answer:

They went from atoms to oxygen molecule.

Explanation:

I'm not sure if this is the answer your teacher is looking for, but in simple terms you had 2 oxygen atoms. Together they make an oxygen molecule, which is the stuff we breathe.

5 0
3 years ago
Wind power is:
12345 [234]
Answer) All of the above
7 0
2 years ago
Read 2 more answers
The relative atomic mass of Chlorine is 35.45. Calculate the percentage abundance of the two isotopes of Chlorine, 35Cl and 37Cl
nata0808 [166]

Answer:

35Cl = 75.9 %

37Cl = 24.1 %

Explanation:

Step 1: Data given

The relative atomic mass of Chlorine = 35.45 amu

Mass of the isotopes:

35Cl = 34.96885269 amu

37Cl = 36.96590258 amu

Step 2: Calculate percentage abundance

35.45 = x*34.96885269 + y*36.96590258

x+y = 1  x = 1-y

35.45 = (1-y)*34.96885269 + y*36.96590258

35.45 = 34.96885269 - 34.96885269y +36.96590258y

0.48114731 = 1,99704989‬y

y = 0.241 = 24.1 %

35Cl = 34.96885269 amu = 75.9 %

37Cl = 36.96590258 amu = 24.1 %

3 0
2 years ago
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