Answer:
401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.
Explanation:
The expression for the standard change in free energy is:
Where,
is the change in the Gibbs free energy.
T is the absolute temperature. (T in kelvins)
is the enthalpy change of the reaction.
is the change in entropy.
Given at:-
Temperature = 25.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25.0 + 273.15) K = 298.15 K
= 128.9 kJ/mol
= 33.1 kJ/mol
Applying in the above equation, we get as:-

= 0.32131 kJ/Kmol
So, For reaction to be spontaneous, 
Thus, For minimum temperature:-

<u>Hence, 401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.</u>
Answer:Metallic bonding As you can see, an electron is freely moving from one atom to another. As one metal atom loses an electron and becomes a positively charge ion, it immediately accepts one from another to become a neutral atom. This back and forth losing and gaining of electrons among atoms of the metal allow metals to easily conduct electricity.
Explanation:
Metallic bonding As you can see, an electron is freely moving from one atom to another. As one metal atom loses an electron and becomes a positively charge ion, it immediately accepts one from another to become a neutral atom. This back and forth losing and gaining of electrons among atoms of the metal allow metals to easily conduct electricity.
The reaction is that,
1 mole is SiCL4 will produce 1 mole of Si(s) Since there is 1 to 1 relationship then we just multiply the enthalpy of reaction by the number of moles
Enthalpy = -625.5 kJ/mole × 12.5 Moles
= -7,818.75 KJ
= -0.78 ×10⁴KJ
Answer is: the oxidation number of oxygen must decrease.
Oxidizing agent is element (substance) that gain electrons in chemical reaction.
For example, balanced chemical reaction: C + O₂ → CO₂.
Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)
n = 5
l = 0,1,2,3,4
ml = -4,-3,-2,-1,0,1,2,3,4,
ms = +1/2 and -1/2