<span>The molar heat of solution of NaOH is -445,100 J/mol. To compute much heat (in J) will be released if 40.00 g of NaOH are dissolved in water, we first convert the given grams of NaOH to moles of NaOH, and use the given molar heat of solution to compute for the energy. (Using dimensional analysis):
40 g NaOH x (1 mol NaOH/ 40 g NaOH) x (-445100 J / 1 mol NaOH) = -445100 J of energy.</span>
Answer:
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Answer: 241. 8g. Add the mass of Fe, 3 N masses (because of the 3 outside the parenthesis), and add the 9 O because of the 3 next to it and the 3 outside. This results to 55.846+42.0201+143.946g that equals 241.8g. I hope this helps
Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles