Answer: -
Thus Colligative properties depend most on concentration of solute particles.
Explanation: -
Colligative properties are the properties of a solution that depends only on the number of particles of the solute present in the solution and not on the identity of the solute.
The number of solute particles present per unit volume in a solution is referred to as the concentration of solute particles.
Thus Colligative properties depend most on concentration of solute particles.
Explanation:
a) Cr is <u>acid</u> K is <u>base</u>
b) Ca is <u>base</u> and the other left part is <u>acid</u>
c)Ca is <u>base</u> and F2 is <u>acid</u>
<u>d</u><u>)</u><u> </u>NH4 is <u>acid</u> and SO4 is <u>base</u>
Answer:
La afirmación es verdadera.
Explanation:
El método científico es un método de investigación usado principalmente en la producción de conocimiento en las ciencias y se define como un procedimiento para tratar un conjunto de problemas. En ciencia, el método científico es la estrategia para la investigación y la exploración de lo desconocido.
Por lo que el método científico es el procedimiento mediante el cual es posible alcanzar un conocimiento objetivo de la realidad, tratando de dar respuesta a las interrogantes acerca del orden de la naturaleza.
Para ser científico, un método de investigación debe basarse en la empírica y en la medición, sujeto a los principios específicos de las pruebas de razonamiento.
El método científico se basa en la reproducibilidad, es decir, la capacidad de repetir un determinado experimento, en cualquier lugar y por cualquier persona, y la refutabilidad, es decir toda proposición científica tiene que ser susceptible de ser falsada o refutada.
Entonces <u><em>la afirmación es verdadera.</em></u>
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
