Answer:
A drug administered at a rate of 13.5 cL/hour has a rate in μL/s of 37.5 μL/s
Explanation:
The given rate at which the blood is administered = 13.5 cL/hour
The rate at which the question asked to be administered = μL/s
The conversion factor between cL and μL is given as follows;
1 cL = 10,000 μL
Which gives;
13.5 cL/hour × 10,000 μL/cL × 1 hour/(60 × 60 seconds) = 37.5 μL/s
Therefore, a drug administered at a rate of 13.5 cL/hour has an administration rate of 37.5 μL/s.
Answer: (1). There are 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP.
(2). The density of gaseous arsine is 3.45 g/L.
Explanation:
1). At STP the pressure is 1 atm and temperature is 273.15 K. So, using the ideal gas equation number of moles are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
2). As number of moles are also equal to mass of a substance divided by its molar mass.
So, number of moles of Arsine (molar mass = 77.95 g/mol) is as follows.
Density is the mass of substance divided by its volume. Hence, density of arsine is calculated as follows.
Thus, we can conclude that 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP and the density of gaseous arsine is 3.45 g/L.
Answer: A longer answer is as follows: Species naturally change their ranges over time, ... By Definition, an invasive species is a plant or an animal or even a pathogen ... Any references to empirical studies that support your thesis on ... part of a process we do not desire (because of its potential negative effect on ...
Explanation:
Answer:
The farther it is the weaker the forces gets.
Explanation:
Take a magnet as a example, if it's close it will attract, but if it's far away then it cannot attract.
Answer:
0.725 kg
Explanation:
Step 1: Given data
- Kinetic energy of the softball (K): 145 J
- Speed of the softball (v): 20.0 m/s
- Mass of the softball (m): ?
Step 2: Calculate the mass of the softball
We will use the following expression.
K = 1/2 × m × v²
m = 2 K / v²
m = 2 × 145 J / (20.0 m/s)²
m = 0.725 kg
The mass of the softball is 0.725 kg.