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Tju [1.3M]
3 years ago
9

Mr. Smith spent 6 hours hiking along a trail and back. He walked out at the rate of 4 miles per hour and walked back at the rate

of 2 miles per hour. How long did it take Mr. Smith to get to the end of the trial?
Mathematics
1 answer:
ollegr [7]3 years ago
5 0
To get to the end of the trail it would take 2 hours because the walking back hours would be double the walking out rate, but it would still have to equal 6 hours. So walking out would be 2 hours and walking back would be 4 hours which makes the trail 8 miles long.
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Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

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Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

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Sky is the limit.

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vodomira [7]

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