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3 years ago

The magnitude of a component of a vector must be:

Physics

1 answer:

fenix001 [56]3 years ago

6 0

Answer:

(d) Less than or equal to the magnitude of vector

Explanation:

The magnitude of any vector is vector sum of magnitude of its component

As magnitude of vector is sum of its component so magnitude of its component never be greater than the magnitude of vector

It can be equal to the magnitude of vector in one case when the magnitude of other component of the vector is zero

So it can be less or equal to the magnitude of vector

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Please help me with the question below the best answer with an explanation will get brainliest

lesya [120]

Answer:

Explanation:

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2 years ago

You apply a net force on a soccer ball of 15 N. If the acceleration it has is 5 m/s2 what is the mass of the ball?

Ipatiy [6.2K]

Answer:

Explanation:

The mass of the ball can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

We have

$m = \frac{15}{5} = 3 \\$

We have the final answer as

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3 years ago

A researcher measures the thickness of a layer of benzene (n = 1.50) floating on water by shining monochromatic light onto the f

NNADVOKAT [17]

Answer:

Explanation:

This problem relates to interference of light in thin films .

The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index is as follows.

2nt = (2n+1) λ / 2 , n is refractive index of thin layer , t is its thickness , λ is wavelength of light .

2 x 1.5 t = λ / 2 , if n = 0 for minimum thickness.

2 x 1.5 t = 600 / 2 nm

t = 100 nm .

5 0

3 years ago

(3)science who ever gets this right will get a brainlest

lara [203]

Answer:

True.

Explanation:

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3 years ago

A cube of water 10 cm on a side is placed in a microwave beam having Ea = 11 kV/m‘ The microwaves illuminate one faceofthe cube,

Shtirlitz [24]

Answer:

The time is 133.5 sec.

Explanation:

Given that,

One side of cube = 10 cm

Intensity of electric field = 11 kV/m

Suppose How long will it take to raise the water temperature by 41°C Assume that the water has no heat loss during this time.

We need to calculate the rate of energy transfer from the beam to the cube

Using formula of rate of energy

$P=(0.80)IA$

$P=0.80\times\dfrac{c\mu_{0}E^2}{2}\times A$

Put the value into the formula

$P=0.80\times\dfrac{3\times10^{8}\times8.85\times10^{-12}\times(1.1\times10^{4})^2}{2}\times(10\times10^{-2})^2$

$P=1285.02\ W$

We need to calculate the amount of heat

Using formula of heat

$E =mc\Delta T$

$E =\rho Vc\Delta T$

Put the value into the formula

$E=1000\times(0.10)^3\times4186\times41$

$E=171626\ J$

We need to calculate the time

Using formula of time

$t=\dfrac{E}{P}$

Put the value into the formula

$t=\dfrac{171626}{1285.02}$

$t=133.5\ sec$

Hence, The time is 133.5 sec.

3 0

4 years ago