Answer:
Explanation:
F = ma
<u>Assuming</u> the 20° is angle θ measured to the horizontal
mgsinθ - μmgcosθ = ma
g(sinθ - μcosθ) = a
at constant velocity, a = 0
g(sinθ - μcosθ) = 0
sinθ - μcosθ = 0
sinθ = μcosθ
μ = sinθ/cosθ
μ = tanθ
μ = tan20
μ = 0.3639702342...
μ = 0.36
Answer: Speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Explanation: To find the answer, we need to know more about the Orbital and escape velocities.
<h3>
What is Orbital and Escape velocity?</h3>
- Orbital velocity can be defined as the minimum velocity required to put the satellite in its orbit around the earth.
- The expression for orbital velocity near to the surface of earth will be,

- Escape velocity can be defined as the minimum velocity with which a body must be projected from the surface of earth, so that it escapes from the gravitational field of earth.
- The expression for orbital velocity will be,

- If we want to get into the sun, we want to slow down almost completely, so that your speed relative to the sun became almost zero.
- We need about twice the raw speed to go to the sun than to leave the sun.
Thus, we can conclude that, the speeding up the orbital speed of earth so it escapes the sun require the greater energy.
Learn more about orbital and escape velocity here:
brainly.com/question/28045208
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They differ because they are transverse wave. That is their direction of travel is perpendicular to its vibrations.
Using the kinematic equation d = V_0 * t + 1/2 * a * t^2, where d is height you can rewrite this to be d = 1/2*g*t^2 or 4.9t^2
g = a because this is a free fall
d = 1/2 * 9.81m/s^2 * 2.5^2
d = 30.65625m
d = 30.7m
The answer is a property of density. The higher the density, the higher the pressure at the bottom.
Pressure = mass / Area. So given that the 4 samples occupy the same area at the bottom, the mass is going to be the determining factor. Per given volume, mercury has the largest mass. The answer is A