Use round wheels to roll the heap, help the weight by evacuating appended or contained protests, or place a smoother surface betwen the question and the floor. Water or different liquids can be utilized to diminish the protection, yet just on the off chance that they stay between the question and the floor.
question: Please help!!!
If a bottle is being squeezed with a force of 10 Newtons and the area of the bottle is 15
squared inches. What is the pressure??
Answer:
1025.64 N/m²
Explanation:
Pressure: This can be defined as the ratio of force to area. The si unit of pressure is N/m².
From the question,
P = F/A........................ Equation 1
Where F = Force, A = Area.
Given: F = 10 Newtons, A = 15 Squared Inches = (15×0.00065) = 0.00975 m²
Substitute these values into equation 1
P = 10/0.00975
P = 1025.64 N/m²
Hence the pressure of the bottle is 1025.64 N/m²
The average kinetic energy of the molecules of the coffee will decrease and the speed of the individual molecules will also reduce.
<h3>
Temperature of resultant mixture</h3>
The temperature of the resultant mixture will be higher than the cold water temperature and lower than the hot coffee temperature.
Based on the decrease of the resulting temperature (equilibrium temperature) of the mixture, the average kinetic energy of the molecules of the coffee will decrease and the speed of the individual molecules of the hot coffee mixture will reduce, leading to a resultant cold mixture of coffee.
Learn more about kinetic molecular model here: brainly.com/question/2901837
Answer:
Explanation:
The period of the comet is the time it takes to do a complete orbit:
T=1951-(-563)=2514 years
writen in seconds:
Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.
Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:
![T^2=\frac{4\pi^2}{Gm_{sun}}a^3\\ a=\sqrt[3]{\frac{Gm_{sun}T^2}{4\pi^2} } \\a=1.50*10^{6}m](https://tex.z-dn.net/?f=T%5E2%3D%5Cfrac%7B4%5Cpi%5E2%7D%7BGm_%7Bsun%7D%7Da%5E3%5C%5C%20a%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BGm_%7Bsun%7DT%5E2%7D%7B4%5Cpi%5E2%7D%20%7D%20%5C%5Ca%3D1.50%2A10%5E%7B6%7Dm)
Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:
